Women can not be colorblind, only men. For questions like these a punnett square is useful. Men can not carry the colorblind trait, but women can. I know this is kind of confusing.
When a carrier ( a woman with the color blind trait) has children with a man ( color blind or not) her kids will have 50% chance of having that trait. If its a girl, she will be the carrier. If its a boy, he will have the colorblind trait.
SO TO ANSWER YOUR QUESTION:
Theoreticaly, 1 of the daughters will be the carrier, and the son will have a 50% chance of being colorblind.
Women can be colorblind, its just rare. About every 6400 women one is colour blind and with men, every 80 men 1 is colour blind.
It is located on the X-Chromosome only.
the x chromosome only
The alleles on the sex chromosomes are still dominant or recessive, the difference is that even a recessive trait on the X chromosome can be expressed if it is located at a gene locus that has no matching locus on the Y chromosome. The alleles for red-green color blindness are located on the X chromosome is a place that has no corresponding locus on the Y chromosome. Inheritance for a male child depends on the mother's genetics and, if she is a carrier, the male child has a 50% chance of being color blind.
if seed color and shape were located on the same chromosome
Males only have one copy of the X chromosome
i don't know... is there a genetic connection??? Im wondering the same thing. Is there a genetic connection? I concluded that there is not an genetic connection, that dark hair has dark eyes for example. But i do however thing that there is a environmental connection. Both hair and eye color is effected but the environment (sunny, not sunny)
Sexlinked traits follow a different pattern of inheritance than a non-sex linked trait because of the size difference between the X and y chromosomes. Think about non-sex chormosomes as being the same size, each having the exact same number of genes in the same postions (loci). This means that a person has to have two copies of the recessive genes (one on each homolog of that chromosome) before the trait will be expressed. Lets say A is normal (dominant) and a is abnormal (recessive). People who are aa have the abnormal condition and people who are AA or Aa are normal. The normal ratio is 1 AA:2 Aa:1 aa if both parents are Aa. There is a 25% chance that a child will inherit two abnormal genes and the chance of any sex child will be so affected is exactly the same. When a recessive trait is located on the X chromosome only a female with two X chromosomes has the same number of genes on each X chromosome (the two X chromosomes have the same inheritance behavior as a homolog chromosome in females). In males who inherit the much smaller y chromosome there are many genes on the X chromosome that do not have a matching gene on the y chromosome. This means that recessive traits on the X chromosome that have no matching genetic material on the y chromosome will always be expressed. So, lets say that there is a family where the mother is Aa and the father (who only has one allele on the y chromosome is A. (A is normal and a is abnormal). None of the daughters produced can be aa, because the father will always pass A. Daughters will only be Aa or AA. Sons on the other hand, will get either A or a from the mother and, since the y chromosome has no genetic material at this gene locus the boys will be A normal or a affected at in a 1:1 ratio. If the father is a on his X chromosome, and the mother is AA 100% of the daughters will be carriers (Aa) and all the sons will be normal (A-).
The alleles on the sex chromosomes are still dominant or recessive, the difference is that even a recessive trait on the X chromosome can be expressed if it is located at a gene locus that has no matching locus on the Y chromosome. The alleles for red-green color blindness are located on the X chromosome is a place that has no corresponding locus on the Y chromosome. Inheritance for a male child depends on the mother's genetics and, if she is a carrier, the male child has a 50% chance of being color blind.
female.
if seed color and shape were located on the same chromosome
Males only have one copy of the X chromosome
An x-linked recessive trait is a trait located on a x gene that is not dominant. It typically will show up when there is only 1 x gene, in the instance of males. Color blindness is an example.
i don't know... is there a genetic connection??? Im wondering the same thing. Is there a genetic connection? I concluded that there is not an genetic connection, that dark hair has dark eyes for example. But i do however thing that there is a environmental connection. Both hair and eye color is effected but the environment (sunny, not sunny)
Sounds like the disorder is genetic and located in his x-chromosome.
Sounds like the disorder is genetic and located in his x-chromosome.
Sexlinked traits follow a different pattern of inheritance than a non-sex linked trait because of the size difference between the X and y chromosomes. Think about non-sex chormosomes as being the same size, each having the exact same number of genes in the same postions (loci). This means that a person has to have two copies of the recessive genes (one on each homolog of that chromosome) before the trait will be expressed. Lets say A is normal (dominant) and a is abnormal (recessive). People who are aa have the abnormal condition and people who are AA or Aa are normal. The normal ratio is 1 AA:2 Aa:1 aa if both parents are Aa. There is a 25% chance that a child will inherit two abnormal genes and the chance of any sex child will be so affected is exactly the same. When a recessive trait is located on the X chromosome only a female with two X chromosomes has the same number of genes on each X chromosome (the two X chromosomes have the same inheritance behavior as a homolog chromosome in females). In males who inherit the much smaller y chromosome there are many genes on the X chromosome that do not have a matching gene on the y chromosome. This means that recessive traits on the X chromosome that have no matching genetic material on the y chromosome will always be expressed. So, lets say that there is a family where the mother is Aa and the father (who only has one allele on the y chromosome is A. (A is normal and a is abnormal). None of the daughters produced can be aa, because the father will always pass A. Daughters will only be Aa or AA. Sons on the other hand, will get either A or a from the mother and, since the y chromosome has no genetic material at this gene locus the boys will be A normal or a affected at in a 1:1 ratio. If the father is a on his X chromosome, and the mother is AA 100% of the daughters will be carriers (Aa) and all the sons will be normal (A-).
It is carried on the X chromosome.
Typically the X-chromosome, which makes it more common in men. The mutation can also occur on 19 other chromosomes, but X is the clearest one.
It is rare in females because they have 2 X chromosomes so they have the trait that stops colorblindness, but men have an X and Y chromosome so the Y chromosome does not back up the other X chromosome and makes men have more of a chance to get colorblindness that doesn't mean girls cant get it, just means girls have a better chance to stop it.