The gas pressure in an aerosol can is 1.8 ATM at 25oC If the gas is an ideal gas what pressure would develop in the can if it were heated to 475oC?

Answer 1

4.5181 atm

P1/T1 = P2/T2

where T = temp in Kelvin

Answer 2

Using the ideal gas law (PV = nRT), we can calculate the new pressure of the gas in the aerosol can. Given that the initial pressure (P1) is 1.8 ATM and the initial temperature (T1) is 25°C, we can rearrange the formula to find the new pressure (P2) at 475°C. Since the volume (V), moles of gas (n), and gas constant (R) remain constant, we can solve for P2: P2 = (P1 * T2) / T1 = (1.8 ATM * 748 K) / 298 K ≈ 4.5 ATM.