The molecular structure for 2,2-dimethylbutane is C6H14.
How to get: 2,2-dimethylbutane
After getting your structual formula wrote down, count up all the carbon atoms. You should get six. Then count all your hydrogen atoms. You should get fourteen.
58.1222 g/mol
These isomers have different molecular structures.
The molecular formula of Butane is C4H10. It's an organic compound that is a gas at room temperature, and is highly flammable, colorless, easily liquefied. The structure of n-Butane is CH3-CH2-CH2-CH3.
The empirical formula of C2H5 corresponds to an empirical mass of 29 g/mol. To find the molecular formula from the empirical formula and molecular mass, divide the molecular mass by the empirical mass to get the "scaling factor" (58 g/mol ÷ 29 g/mol = 2). Multiply the subscripts in the empirical formula by the scaling factor to get the molecular formula: C2H5 x 2 = C4H10. So, the molecular formula is C4H10.
The molar mass of butane is 58,124; for mr explain this abbreviation.
58
58.1222 g/mol
The melting and boiling points are different. Butane has a melting point of 135.4K and 2-methylpropane [isobutane] has a melting point of 114K. The boiling point of Butane is 272.6K and isobutane @ 261K. It has to do with there structures. J
Butane
These isomers have different molecular structures.
C4H10 is the molecular formula for butane, as it represents the actual number of atoms of each element in a single molecule of the compound. The empirical formula for butane would be CH5, as it shows the simplest whole number ratio of atoms present in the compound.
The molar mass of butane (C4H10) is 58.12 g/mol. The molar mass of hydrogen in butane is 10.81 g/mol. To calculate the mass percent of hydrogen in butane, you would divide the molar mass of hydrogen by the molar mass of butane and multiply by 100. This gives you a mass percent of approximately 18.6%.
Yes, the molecular mass of propane is 44 while that of butane is 58, higher is the molecular mass of an alkane higher would be the boiling point therefore less would be the volatility.
BUTANE!
The molecular formula of Butane is C4H10. It's an organic compound that is a gas at room temperature, and is highly flammable, colorless, easily liquefied. The structure of n-Butane is CH3-CH2-CH2-CH3.
The empirical formula of C2H5 corresponds to an empirical mass of 29 g/mol. To find the molecular formula from the empirical formula and molecular mass, divide the molecular mass by the empirical mass to get the "scaling factor" (58 g/mol ÷ 29 g/mol = 2). Multiply the subscripts in the empirical formula by the scaling factor to get the molecular formula: C2H5 x 2 = C4H10. So, the molecular formula is C4H10.
4 Carbon atoms in one molecule of Butane, times 2 because of two molecules, time the weight of one Carbon atom, which is 12 amu's (an amu = atomic mass unit, also known as a Dalton) equals 96 amu's.