I will assume that you will start from the crystals of permanganate:
Calculations:
M.M. potassium permanganate: 158.04 g/mol
mol KMnO4 in 10mL sol'n: 1.5 mol/L x 10 mL x (1 L / 1000 mL) = 0.015 mol
grams potassium permanganate: 0.015 mol x 158.04 g/mol = 2.3706 g / 10 mL sol'n
Preparation:
1. Weigh out analytically 2.3706g KMnO4 into a 10 mL volumetric flask.
2. Dilute to the mark with dH2O.
Chat with our AI personalities
To prepare a 100 ppm (parts per million) solution of KMnO4, you would dissolve 0.1 grams of KMnO4 in 1 liter of water. This concentration means there are 100 milligrams of KMnO4 dissolved in 1 liter of solution.
First we look at the equation involving KMnO4 in Redox reaction.
MnO4- + 8H+ + 5e- -------> Mn2+ + 4H2O
Hence 5 electrons are transferred in the reaction. Therefore 1N solution of KMnO4 = M/5 solution of KMnO4 i.e., 0.20M KMnO4 solution. Hence 0.1N KMNO4 solution is equivalent to 0.02M KMnO4 i.e., a solution containing 3.1607g/L of KMnO4
1. Weigh 15,803 g ultrapure KMnO4 dried at 110 0C for 30 min.
2. Transfer KMnO4 in a clean 1 L volumetric flask using a funnel. 3. Wash the funnel with 0,9 L demineralized water.
4. Put the flask in a thermostat and maintain 30 min at 20 0C.
5. Add demineralized water up to the mark.
6. Stir vigorously and transfer in a clean bottle with stopper.
7. Add a label with necessary information.
The molar mass of potassium permanganate is 158,034; 2 M KMnO4 equals 316,068 g.
1000 mL----------------------------316,068 g
20 mL-------------------------------x
x= 20 x 316,068/1000 = 6,32 g
-------------------------------------------------------------------
Preparation: Dissolve 6,32 g KMnO4 a.r. dried in 20 mL demineralized water, at 20 oC, in a volumetric flask.
there is tow method to prepare 1n kmno4 it's depend on oxidation number. Iknow one of this method you need 31.6 gms in one L D.WATER IF YOU KNOW FURTHER INFORMATION PLEASE TELL ME.
To prepare a parts per million (ppm) solution from a solid, you would first need to accurately measure the mass of the solid compound. Then, dissolve this solid in a known volume of solvent to make a specific concentration solution. Finally, calculate the ppm concentration by dividing the mass of the solid compound by the total mass of the solution and converting it to ppm.
To make a 100 ppm solution of methanol in 100 mL of water, you would need 10 mg of methanol. This is because 100 ppm is equivalent to 100 mg/L, and since you have 100 mL of water, you would need 10 mg of methanol (100 mg/L x 0.1 L).
Another way to express the concentration of a glucose solution that is 0.01 percent by weight is as 100 parts per million (ppm). This means there are 100 grams of glucose in 1 million grams of solution.
100 kg is equivalent to 100,000 grams. If there are 1 part per million (ppm) of a substance in 1 gram, then there would be 100 ppm in 100 kg.
To dilute 1000 ppm to 500 ppm, you need to add an equal amount of the solution without any concentration. For example, if you have 1 mL of the 1000 ppm solution, you would need to add 1 mL of water to make it 500 ppm.