answersLogoWhite

0

I will assume that you will start from the crystals of permanganate:

Calculations:

M.M. potassium permanganate: 158.04 g/mol

mol KMnO4 in 10mL sol'n: 1.5 mol/L x 10 mL x (1 L / 1000 mL) = 0.015 mol

grams potassium permanganate: 0.015 mol x 158.04 g/mol = 2.3706 g / 10 mL sol'n

Preparation:

1. Weigh out analytically 2.3706g KMnO4 into a 10 mL volumetric flask.

2. Dilute to the mark with dH2O.

User Avatar

Wiki User

17y ago

Still curious? Ask our experts.

Chat with our AI personalities

ReneRene
Change my mind. I dare you.
Chat with Rene
JudyJudy
Simplicity is my specialty.
Chat with Judy
MaxineMaxine
I respect you enough to keep it real.
Chat with Maxine
More answers

To prepare a 100 ppm (parts per million) solution of KMnO4, you would dissolve 0.1 grams of KMnO4 in 1 liter of water. This concentration means there are 100 milligrams of KMnO4 dissolved in 1 liter of solution.

User Avatar

AnswerBot

11mo ago
User Avatar

First we look at the equation involving KMnO4 in Redox reaction.

MnO4- + 8H+ + 5e- -------> Mn2+ + 4H2O

Hence 5 electrons are transferred in the reaction. Therefore 1N solution of KMnO4 = M/5 solution of KMnO4 i.e., 0.20M KMnO4 solution. Hence 0.1N KMNO4 solution is equivalent to 0.02M KMnO4 i.e., a solution containing 3.1607g/L of KMnO4

User Avatar

Wiki User

13y ago
User Avatar

1. Weigh 15,803 g ultrapure KMnO4 dried at 110 0C for 30 min.
2. Transfer KMnO4 in a clean 1 L volumetric flask using a funnel. 3. Wash the funnel with 0,9 L demineralized water.
4. Put the flask in a thermostat and maintain 30 min at 20 0C.
5. Add demineralized water up to the mark.
6. Stir vigorously and transfer in a clean bottle with stopper.
7. Add a label with necessary information.

User Avatar

Wiki User

10y ago
User Avatar

The molar mass of potassium permanganate is 158,034; 2 M KMnO4 equals 316,068 g.
1000 mL----------------------------316,068 g
20 mL-------------------------------x

x= 20 x 316,068/1000 = 6,32 g
-------------------------------------------------------------------
Preparation: Dissolve 6,32 g KMnO4 a.r. dried in 20 mL demineralized water, at 20 oC, in a volumetric flask.

User Avatar

Wiki User

9y ago
User Avatar

there is tow method to prepare 1n kmno4 it's depend on oxidation number. Iknow one of this method you need 31.6 gms in one L D.WATER IF YOU KNOW FURTHER INFORMATION PLEASE TELL ME.

User Avatar

Wiki User

15y ago
User Avatar

By solving 100 mg of KMnO4 in 1 L of distilled water at 20 0C.

User Avatar

Wiki User

15y ago
User Avatar

Dissolve 0,1 g of potassium permanganate in 100mL water.

User Avatar

Wiki User

11y ago
User Avatar

Dissolve 1,58 g KMnO4 for analysis in 1 L distilled water at 20 oC.

User Avatar

Wiki User

7y ago
User Avatar

Dissolve 31,6 g KMnO4 in 1 kg acidified distilled water.

User Avatar

Wiki User

7y ago
User Avatar

Add your answer:

Earn +20 pts
Q: How to prepare 100 ppm solution of KMnO4?
Write your answer...
Submit
Still have questions?
magnify glass
imp