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Molar mass of CuSO4.5H2O = 250 No. of moles = 10.037 / 250 = 0.040 No. of molecules = 0.040 * 6.02 * 10^23 = 2.417 x 10^22 1 molecule of CuSO4.5H2O gives 9 O atoms --> No. of O atoms = 2.417 x 10^22 x 9 = 2.175 x 10^23

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โˆ™ 15y ago
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โˆ™ 5mo ago

To find the number of oxygen atoms in 10.037 grams of CuSO4ยท5H2O, first calculate the molar mass of CuSO4ยท5H2O. Then calculate the number of moles of CuSO4ยท5H2O in 10.037 grams. Finally, use the mole ratio from the chemical formula to determine the number of oxygen atoms present, considering that there are 4 oxygen atoms in each CuSO4ยท5H2O molecule.

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โˆ™ 14y ago

O4 means there are 4 O atoms bonded to 1 Cu atom and 1 S atom

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Q: How to find Number of oxygen atoms in 10.037 grams of CuSO4.5H2O?
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