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How to find Number of oxygen atoms in 10.037 grams of CuSO4.5H2O?
Wiki User
∙ 14y ago
Molar mass of CuSO4.5H2O = 250 No. of moles = 10.037 / 250 = 0.040 No. of molecules = 0.040 * 6.02 * 10^23 = 2.417 x 10^22 1 molecule of CuSO4.5H2O gives 9 O atoms --> No. of O atoms = 2.417 x 10^22 x 9 = 2.175 x 10^23
Wiki User
∙ 14y ago
Anonymous
To find the number of oxygen atoms in 10.037 grams of CuSO4·5H2O, first calculate the molar mass of CuSO4·5H2O. Then calculate the number of moles of CuSO4·5H2O in 10.037 grams. Finally, use the mole ratio from the chemical formula to determine the number of oxygen atoms present, considering that there are 4 oxygen atoms in each CuSO4·5H2O molecule.
Wiki User
∙ 14y agoO4 means there are 4 O atoms bonded to 1 Cu atom and 1 S atom
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