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Ftotal= B - Fg = 0 (B = Buoyant Force; Fg = Weight of mass)

B = Fg

(pf - po) * Vo * g = m * g (p = rho, density of fluid, air, and of object, balloon multiplied by volume of balloon, g cancels out.)

(1800-17) * 200 = m

m = 356600 units (units depends on what density value you were given. Typically they are in kg/m3, but these densities are very high for kg/m3.)

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16y ago
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1mo ago

The lift force of a helium-filled balloon is equal to the weight of the air it displaces minus the weight of the balloon and the gas inside. The difference in density between helium and air is 1783 (1800 - 17). So, the balloon can lift mass equal to the volume of helium multiplied by the density difference, which is 200 m³ * 1783 kg/m³ = 356,600 kg.

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Q: How much mass can a balloon filled with 200 m3 helium lift when the density of helium is 17 and the density of air is 1800?
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