Not a heck of a lot! Here's the number worked out:
Energy of a photon = 'h' times frequency
'h' = Planck's konstant = 6.626 x 10-34 Joule-second
For a 1000-Hz photon, E = (6.626 x 10-34) x (103) = 6.626 x 10-31 Joule =
0.0000000000000000000000000000006626 Joule.
One reason (of many) for why it's so small is the frequency you chose.
1000 Hz is comfortably in the middle of human hearing ... a much lower
frequency than any everyday electromagnetic wave of any kind.
You said "a photon of light". The lowest frequency that you can see with your eyes
is somewhat higher than 1000 Hz, and more like 400,000,000,000,000 Hz. (red light)
The photon (quantum) at gamma frequency has more energy than a photon at microwave frequency has. But you can easily generate a beam of microwaves carrying more energy than, for example, the gamma rays that enter your house from space. Just use a more powerful source of microwaves to generate more photons. No big deal. The one in your kitchen that you use to heat the leftover meatloaf pours out far more energy every second than gamma rays bring into your house, but each microwave photon carries much less energy than a gamma photon does.
-- I have to assume that the '520' figure is also a wavelength in nm.-- The energy of a photon is proportional to its frequency. That also meansthat the energy is inversely proportional to its wavelength. So the photonwith the greater wavelength has less energy.-- 720/520 = 1.385The shorter-wave photon has 38.5% more energy than the longer-wave one.-- 520/720 = 0.722The longer wave photon has 72.2% as much energy as the shorter-wave one has.
Transition B produces light with half the wavelength of Transition A, so the wavelength is 200 nm. This is due to the inverse relationship between energy and wavelength in the electromagnetic spectrum.
Yes, due to the energy of photons/electromagnetic particles being determined by the equations below: E= hv=hc(1/v)= hc/wavelength. Where E= energy, v= frequency in Hz, h= Planck's constant, c= speed of light Electrons have a very short wavelength, and a very high frequency, thus they have much more energy than a beam of light.
Ultraviolet light has more energy than visible light. This is because ultraviolet light has shorter wavelengths and higher frequencies compared to visible light, which results in higher energy levels.
The energy of a photon is given by E = hf, where h is the Planck's constant (6.626 x 10^-34 JΒ·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 6 x 10^12 Hz is approximately 3.98 x 10^-21 Joules.
The energy of a photon is given by the formula E = hf, where h is Planck's constant (6.626 x 10^-34 J s) and f is the frequency of the photon. So, for a photon with a frequency of 6 x 10^12 Hz, the energy would be approximately 3.98 x 10^-21 Joules.
The energy of a photon can be calculated using the equation E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 6 x 10^12 Hz would be approximately 3.98 x 10^-21 Joules.
The energy of a photon is given by the equation E = hf, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency. Plugging in the values, the energy of a photon with a frequency of 6 x 10^12 Hz would be approximately 3.98 x 10^-21 Joules.
A photon is a packet of energy that carries a quantum of energy. It is an elementary particle that is the quantum of the electromagnetic field, including electromagnetic radiation such as light. The energy of a photon is directly proportional to its frequency and inversely proportional to its wavelength.
The longer the wavelength of light, the smaller its frequency, and the less energy there is for every photon.
An X-ray photon has more energy than an infrared photon. X-rays have shorter wavelengths and higher frequencies compared to infrared radiation, resulting in higher energy levels for X-ray photons.
No, microwave photons have less energy than photons of visible light. The energy of a photon is directly proportional to its frequency, where higher frequency photons have higher energy. Microwave photons have lower frequencies than visible light photons, so they have less energy.
The photon (quantum) at gamma frequency has more energy than a photon at microwave frequency has. But you can easily generate a beam of microwaves carrying more energy than, for example, the gamma rays that enter your house from space. Just use a more powerful source of microwaves to generate more photons. No big deal. The one in your kitchen that you use to heat the leftover meatloaf pours out far more energy every second than gamma rays bring into your house, but each microwave photon carries much less energy than a gamma photon does.
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
-- I have to assume that the '520' figure is also a wavelength in nm.-- The energy of a photon is proportional to its frequency. That also meansthat the energy is inversely proportional to its wavelength. So the photonwith the greater wavelength has less energy.-- 720/520 = 1.385The shorter-wave photon has 38.5% more energy than the longer-wave one.-- 520/720 = 0.722The longer wave photon has 72.2% as much energy as the shorter-wave one has.
The energy of a photon of green light with a wavelength of approximately 520 nanometers is about 2.38 electronvolts.