There is a relationship between power P, voltage V and current I. This relationship is best summarised by this formula: P=IV this gives us (current) I = P/V this gives total current =1200/120 =10 ampere
The power flowing through the circuit can be calculated using the formula P = I * V, where P is power, I is current, and V is voltage. In this case, P = 1 amp * 120 volts = 120 watts. Therefore, 120 watts of power flows through the circuit.
To find the current, use Ohm's Law, which states that current (I) equals power (P) divided by voltage (V). For a 60-watt lamp connected to 120 volts, the current is calculated as follows: I = P/V = 60 watts / 120 volts = 0.5 amperes. Therefore, the current flowing through the lamp is 0.5 A.
V = IR Voltage = Current * Resistance so 9 = 0.25 * R Hence R =36 Ohms
12 volts do not have a specific temperature, as voltage refers to electrical potential. The temperature depends on the current flowing through the circuit and the resistance of the components involved. Overheating can occur if too much current flows through a circuit, causing components to heat up and potentially fail. It's important to use proper circuit design and components to prevent overheating.
The amperage flowing through the 60-watt bulb connected to a 120-volt circuit can be calculated using the formula P (power) = V (voltage) x I (current). In this case, the current can be found by rearranging the formula to I = P / V, which gives a current of 0.5 amperes flowing in the bulb.
Ohm's Law Volts = Current x Resistance Amps = V / R 110 / 20 = 5.5 Amps
4 amps
Ohm's Law Voltage = Current x Resistance Answer is 15/300
Assuming that you mean connected to 120 Volts (V) supply, start with Power(P)=Current(I) x Voltage(V), and if P=V*I, then I=P/V. I=12W/120V=0.1A or 100mA and that is your current.
The power flowing through the circuit can be calculated using the formula P = I * V, where P is power, I is current, and V is voltage. In this case, P = 1 amp * 120 volts = 120 watts. Therefore, 120 watts of power flows through the circuit.
Ohms are the unit of resistance you find in Ohms LAw which says Volts = Amps x Ohms. You can get a voltage drop across a resistance, but would have to know what current is being used and you would have a potentiometer in effect. You are not "converting 12V" to 10V, your are essentially loosing two volts through a resistor.
That depends on the voltage which the current flows through. I = P / U I = 1500 / U Where I is the current in Amperes and U is the effective voltage in Volts. (P is the power)
Let R be the resistance, V the voltage, and I the current R = V / I R = 120 / 24 R = 5 ohm
600 VDC.
The three electrical quantities are current voltage and resistance. Current is measured in amperes (A) and is the rate at which electricity flows through a conductor. Voltage is measured in volts (V) and is the electrical force pushing the current through the conductor. Resistance is measured in ohms () and is the opposition to the flow of current. Current - measured in amperes (A) Voltage - measured in volts (V) Resistance - measured in ohms ()
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The voltage tells you nothing about the current flow in amps, it's only the pressure sending current through a circuit. If a 11,000 volt supply is not connected to anything, the current is zero.