5g would remain
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I suppose that you think to the radioactive isotope Cs-17; After 4 years remain 9,122 g.
2 1/2 g
2 1/2 g
As you did not specify an isotope of cesium, I will assume you meant natural cesium. Natural cesium is not radioactive so it does not decay. There will always be the same 10 g of cesium, no matter how long you wait.
The equation for half-life is ... AT = A0 2 (-T/H) ... where A0 is the starting activity, AT is the activity at some time T, and H is the half-life, in units of T. 55134Cs has a half-life of 2.0652 years. Plugging in the known values, we get ... AT = 5.8 2 (-11.5/2.0652) AT = 5.8 2 -5.5685 AT = 0.12222