35.0 moles nitrogen (1 mole N/14.01 grams)
= 2.50 moles nitrogen
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350g is equivalent to approximately 23.3 tablespoons.
That is 23.3 tbsp.
The specific heat capacity of water is 4.184 J/g°C. To raise the temperature of 350 grams of water from 22°C to a higher temperature, you would multiply the mass of water (350g) by the temperature change and the specific heat capacity of water. So, the heat required would be (350g) x (Tfinal - 22°C) x 4.184 J/g°C.
2 liters is equal to 2070 grams. 2070 grams is equal to 4.56 pounds. In each 2 liter you are getting a little extra.
To calculate the heat lost when 350 g of iron cools from 54.1°C to 22.4°C, we can use the formula: [ Q = m \cdot c \cdot \Delta T ] where ( m = 350 , \text{g} ), ( c = 0.450 , \text{J/g°C} ), and ( \Delta T = 54.1°C - 22.4°C = 31.7°C ). Thus, [ Q = 350 , \text{g} \cdot 0.450 , \text{J/g°C} \cdot 31.7°C = 4,935.75 , \text{J} ] Approximately 4,936 Joules of heat is lost.
To find the number of moles in 350g of sodium, divide the given mass by the molar mass of sodium. The molar mass of sodium is approximately 23g/mol. Therefore, 350g of sodium is equal to 350/23 = 15.22 moles.
half of 350g is 175g
350g is equivalent to approximately 23.3 tablespoons.
That is 23.3 tbsp.
Take 5% of 350g = 17.5 g sugarand add 350g -17.5g = 332.5 g solvent (water, most likely, this is 333 mL)
That is 12.346 ounces.
350g is 0.77 (0.771618) pounds.
There are about three and a half cups in 350g of rice. There is 128g in one cup. One gram equals .035 ounces.
7/20
d=m/v m= 350g v= 70cm d=350/70 d=5g/cm
350g of flour is equal to 2.8 cups (or 2 4/5 cups). This would be approximately 2 3/4 cups.
The density of the object is 35 g/cm^3. This is calculated by dividing the mass (350g) by the volume (10cm^3).