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∙ 12y ago1.305 mol CO
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∙ 12y agoTo find the number of moles of carbon monoxide in 36.55 g, you need to use its molar mass. The molar mass of carbon monoxide is 28.01 g/mol. Divide the given mass by the molar mass to find the number of moles: 36.55 g / 28.01 g/mol = 1.30 moles of carbon monoxide.
1,4 moles carbon monoxide are produced.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
The answer is 7,829.10 ex.23 atoms.
350 g sample of CO contain 12,49 moles.
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
1,4 moles carbon monoxide are produced.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
The answer is 7,829.10 ex.23 atoms.
To find the number of moles of CO molecules, divide the given number of molecules by Avogadro's number. Avogadro's number is about 6.022 x 10^23 molecules/mol. Therefore, 7.20 x 10^27 molecules of CO corresponds to 12 moles (7.20 x 10^27 / 6.022 x 10^23).
350 g sample of CO contain 12,49 moles.
To calculate the number of atoms in 63.5 g of carbon monoxide, first determine the number of moles of carbon monoxide using its molar mass (28.01 g/mol). Then, use Avogadro's number (6.022 x 10^23) to convert moles to atoms. A single molecule of carbon monoxide consists of 1 carbon atom and 1 oxygen atom.
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
To determine the mass of carbon monoxide in 2.55 moles, we first find the molar mass of CO, which is 28.01 g/mol. Then, we multiply the molar mass by the number of moles: 28.01 g/mol * 2.55 mol = 71.53 grams of CO in 2.55 moles of the compound.
In order to find number of molecules from moles, you must multiply moles by avagadro's number, which is 6.02*10^23.
There are approximately 4.52 x 10^23 atoms in 0.750 mol of carbon monoxide. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles of carbon monoxide (0.750 mol).
In carbon monoxide (CO), the molar ratio of carbon (C) to oxygen (O) is 1:1. Therefore, in 20 moles of CO, there are 20 moles of carbon. The molar mass of carbon is approximately 12.011 g/mol, so in 20 moles of carbon, there are 20 x 12.011 = 240.22 grams of carbon.
At STP (standard temperature and pressure), 1 mol of any gas occupies 22.4 liters. The molar mass of carbon monoxides is 28.01 g/mol. So, the number of moles in 3.50 grams of carbon monoxide can be calculated. Then, using the ideal gas law, you can determine that 3.50 grams of carbon monoxide at STP would be approximately 0.125 moles and would occupy around 2.8 liters (0.125 moles * 22.4 liters/mol).