There are 0.003659 N2O moles. So there are o.007318 moles of N.
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3.18 mol 70.0gN2O x 1mol N2O/44.013g x 2mol N/1mol N2O
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
There is no nitrogen in water.
The formula weight for dinitrogen monoxide (N2O) is calculated by adding the atomic weights of nitrogen (N) and oxygen (O) together: N2O = 2(N) + 1(O) = 2(14.01) + 1(16.00) = 28.02 + 16.00 = 44.02 g/mol.
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.