3.18 mol 70.0gN2O x 1mol N2O/44.013g x 2mol N/1mol N2O
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
There is no nitrogen in water.
The formula weight for dinitrogen monoxide (N2O) is calculated by adding the atomic weights of nitrogen (N) and oxygen (O) together: N2O = 2(N) + 1(O) = 2(14.01) + 1(16.00) = 28.02 + 16.00 = 44.02 g/mol.
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
To find the number of moles of N in N2O, we need to use the molar mass of N2O. The molar mass of N2O is 44.02 g/mol. First, calculate the moles of N2O: 0.189g / 44.02 g/mol = 0.0043 moles of N2O Since each N2O molecule contains 2 nitrogen atoms, the number of moles of N is: 0.0043 moles * 2 = 0.0086 moles of N.
To find the number of moles of N in N2O, we first calculate its molar mass. For N2O, the molar mass is 44 g/mol. Next, we convert the given mass of 0.245 g to moles using the formula moles = mass / molar mass. Therefore, in 0.245 g of N2O, there are approximately 0.0056 moles of N.
To find the number of moles of nitrogen in 80.0 grams of nitrous oxide (N2O), we need to calculate the molar mass of N2O, which is 44.02 g/mol. Next, we set up a proportion to calculate the number of moles of nitrogen (N) based on the molar ratio of nitrogen to nitrous oxide in the chemical formula, which is 1:2. Therefore, 80.0 grams of N2O is equivalent to 1.82 moles of N, which you can calculate as (80.0 g N2O) * (1 mol N2O/44.02 g N2O) * (1 mol N/2 mol N2O).
To find the number of moles of nitrogen in 73.0 g of nitrous oxide (N2O), we first need to determine the molar mass of N2O, which is 44.02 g/mol. In N2O, there are 2 atoms of nitrogen per molecule. Thus, the number of moles of nitrogen in 73.0 g of N2O would be calculated as (73.0 g / 44.02 g/mol) * 2 = 3.32 moles of nitrogen.
One molecule of N2O N 2 O contains one atom of oxygen.
To determine the number of moles of nitrogen (N) in 83.0 g of nitrous oxide (N2O), you first need to calculate the molar mass of N2O (nitrous oxide). Molar mass of nitrous oxide (N2O) = 44.02 g/mol. The molar mass of N in N2O is 28.01 g/mol. Therefore, for every mole of nitrous oxide (N2O), there is 2 moles of nitrogen. Using the molar mass ratio, you can calculate the moles of nitrogen in 83.0 g of nitrous oxide.
3.18 mol 70.0gN2O x 1mol N2O/44.013g x 2mol N/1mol N2O
To calculate the number of moles of nitrogen in 67.0 g of nitrous oxide (N2O), first determine the molar mass of N2O (44 g/mol). N2O has two nitrogen atoms, so the molar mass of nitrogen is 28.02 g/mol. Divide the mass of N2O by the molar mass of nitrogen to find the number of moles of nitrogen, which in this case would be approximately 2.39 moles.
To find the moles of N in N2O, you need to calculate the molar mass of N2O (44.02 g/mol) and the weight fraction of N in N2O (28/44.02). Then, divide the weight of N (0.245g) by the molar mass of N (14.01 g/mol) to find the moles of N.
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To find the grams of nitrogen (N) in 34.0g of N2O, you need to consider the molar mass of N2O (44.02 g/mol) where 28.02 g out of 44.02 g is nitrogen. Therefore, in 34.0g of N2O, there are 34.0g * (28.02g/44.02g) = 21.6g of N.
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3