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What is the number of moles in 510 g of Al2S3?
510 g Al2S3 is equal to 3,396 moles.
What is the mass of Al formed when 0.500 moles Al2S3 is reduced completely with excess H2?
To determine the mass of aluminum (Al) formed from the complete reduction of 0.500 moles of aluminum sulfide (Al2S3), we first need to establish the stoichiometry of the reaction. The balanced equation for the reduction of Al2S3 is: [ Al2S3 + 6H2 \rightarrow 2Al + 3H2S. ] From this equation, one mole of Al2S3 produces two moles of Al. Therefore, 0.500 moles of Al2S3 will yield (0.500 \times 2 = 1.000) moles of Al. The molar mass of aluminum is approximately 27.0 g/mol, so the mass of Al produced is (1.000 , \text{mol} \times 27.0 , \text{g/mol} = 27.0 , \text{g}).
How many moles of each element are present in a 100 g sample of deoxyribose?
Deoxyribose has the chemical formula C₅H₁₀O₃. In a 100 g sample of deoxyribose, the number of moles can be calculated using its molar mass, which is approximately 134.13 g/mol. Thus, the number of moles of deoxyribose is about 0.746 moles. Consequently, there would be 0.746 moles of carbon, 1.492 moles of hydrogen, and 0.746 moles of oxygen in the sample.
How many moles in human albumin?
The number of moles in human albumin depends on the specific mass of the albumin sample being considered. Human serum albumin has a molecular weight of approximately 66,500 g/mol. To calculate the moles, you would divide the mass of the albumin sample in grams by its molecular weight (66.5 g/mol). For example, if you have 100 grams of albumin, you would have about 1.5 moles (100 g / 66.5 g/mol).
How many grams of argon are in 100 mole?
To find the mass of argon in grams for 100 moles, you can use the molar mass of argon, which is approximately 40 grams per mole. Therefore, the mass of 100 moles of argon would be calculated as follows: 100 moles × 40 g/mole = 4000 grams. Thus, there are 4000 grams of argon in 100 moles.
What is the number of moles in 510 g of Al2S3?
510 g Al2S3 is equal to 3,396 moles.
How many grams of Al2S3 can be formed from the reaction of 108.00 grams of Al with 5.00 grams of S?
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
How many moles of phosphorus atoms are in a 100 g sample of phosphorus?
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
How many moles of sodium borohydride are used in 100 mg?
To calculate the number of moles of sodium borohydride in 100 mg, you need to know the molar mass of the compound, which is 37.83 g/mol. First, convert 100 mg to grams (0.1 g), then divide by the molar mass to get the number of moles, which is approximately 0.0026 moles.
How many moles are in 100g of KMnO4?
1 mol = 118.94 1 mol / 118.94 = 1.70 / x G = 202.10g
HOW MANY moles of mg atom are there in 100 gm of mg?
The atomic weight of magnesium is 24.31; therefore, the number of moles in 100 gm is 100/24.31 = 4.11, to the justified number of significant digits.
How many moles of phosphorus atoms are in 100 grams of P4S10?
To find the number of moles of phosphorus atoms in 100 grams of P4S10, we first need to determine the molar mass of P4S10 which is 284.26 g/mol. Next, we calculate the number of moles of P4S10 in 100 grams by dividing 100 g by the molar mass to get 0.352 moles of P4S10. Since there are 4 phosphorus atoms in each P4S10 molecule, there are 0.352 moles x 4 = 1.41 moles of phosphorus atoms in 100 grams of P4S10.
What is the number of moles in 100 g MgCO3?
Ah, isn't that a lovely question? To find the number of moles in 100 g of MgCO3, we first need to know the molar mass of magnesium carbonate (MgCO3). Then, we can use the formula: moles = mass / molar mass. Just like painting a happy little tree, it's all about following the steps and enjoying the journey to the answer.
How many atoms of aluminum are there in a sample of aluminum sulfide with a mass of 100 g?
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
If you have g of beryllium how many moles is this equivalent to?
The formula is: number of moles = g Be/9,012.
How many moles are in 978 g Ca?
978 g calcium contain 24,4 moles.
How many moles are in 29.0 g of calcium?
29,0 g of calcium is equal to 0,723 moles.
