answersLogoWhite

0

- molar mass: 34,08 g
- density: 1,363 g/cm3
Mass of H2S: 1,363 x 9,36 = 12,758 g
34,08--------------------------1 mol
12,758-------------------------x
x = 0,374 moles

User Avatar

Wiki User

8y ago

Still curious? Ask our experts.

Chat with our AI personalities

CoachCoach
Success isn't just about winning—it's about vision, patience, and playing the long game.
Chat with Coach
JordanJordan
Looking for a career mentor? I've seen my fair share of shake-ups.
Chat with Jordan
LaoLao
The path is yours to walk; I am only here to hold up a mirror.
Chat with Lao
More answers

At STP? I must assume STP since you mention no temperature or pressure. The formula would be the same anyway, so.......

PV = nRT

(1 atm)(9.63 L) = n(0.08206 L*atm/mol*K)(298.15 K)

9.63/24.466 = n(moles H2)

0.394 moles of hydrogen gas

-------------------------------------

User Avatar

Wiki User

13y ago
User Avatar

At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. Therefore, in 10.3 L of helium gas at STP, the number of moles would be 10.3 L / 22.4 L/mol = 0.460 moles.

User Avatar

AnswerBot

9mo ago
User Avatar

0.43 moles, since 1 mole of gas occupies 22.4 L at STP.

User Avatar

Wiki User

11y ago
User Avatar

In 11.2 L gas (of any kind, even mixtures such as air) at STP contains always 0.50 mole gaseous particles.

User Avatar

Wiki User

12y ago
User Avatar

There is a mole of H2 in 24dm3 (24 liters) of H2 in STP. So there will be 1/24 (0.0417, accurate to 3 sig fig) mole of H2 gas in 1 liter of H2 in STP.

User Avatar

Wiki User

13y ago
User Avatar

0.460

User Avatar

Maria Ramirez

Lvl 2
3y ago
User Avatar
User Avatar

Mable Zboncak

Lvl 1
3y ago
I agree with this answer

.430 mol

User Avatar

Wiki User

12y ago
User Avatar

.459 mol

User Avatar

Wiki User

13y ago
User Avatar

Add your answer:

Earn +20 pts
Q: How many moles are in 10.3 L of helium gas at STP?
Write your answer...
Submit
Still have questions?
magnify glass
imp