6.022 x 1023 x 2 = 1.2044 x 1024
The answer is 64,9 moles.
211g of carbon dioxide are equal to 4,794 moles.
550 g of nitrogen dioxide is equal to 11,94 moles.
There are approximately 1.8 x 10^22 molecules in 0.03 mol of carbon dioxide. This is calculated by multiplying Avogadro's number (6.02 x 10^23) by the number of moles.
Six molecules of carbon dioxide are used to produce one 6-carbon sugar molecule through the process of photosynthesis.
To convert from molecules to moles, divide the given number of molecules by Avogadro's number, which is 6.022 x 10^23. Therefore, for 2.22 x 10^23 molecules of carbon dioxide, divide by Avogadro's number to find 0.368 moles of carbon dioxide.
= 9403.41
To find the number of moles, divide the number of molecules by Avogadro's number, which is (6.022 \times 10^{23}) molecules/mol. (3.75 \times 10^{24}) molecules of carbon dioxide is equivalent to 3.75 moles of carbon dioxide.
There are 1.64 x 10^24 carbon dioxide molecules in 6.82 moles of carbon dioxide. This can be calculated by multiplying Avogadro's number (6.022 x 10^23 molecules/mol) by the number of moles.
There are 2.26 x 10^24 carbon dioxide molecules in 3.74 moles of carbon dioxide. This can be calculated using Avogadro's number (6.022 x 10^23 molecules/mol) multiplied by the number of moles.
The answer is 64,9 moles.
6.32 mol carbon dioxide
There are approximately 1.27 x 10^24 molecules in 2.10 moles of carbon dioxide. This can be calculated using Avogadro's number, which is 6.022 x 10^23 molecules/mol.
There are approx 2.05*1025 molecules.
One mole of carbon dioxide molecules contains one mole of carbon atoms and two moles of oxygen atoms. Therefore, in half a mole of carbon dioxide molecules, there are half a mole of carbon atoms and one mole of oxygen atoms.
To determine the number of moles of carbon dioxide, you can use Avogadro's number, which equates 1 mole to 6.022 x 10^23 molecules. Therefore, 3.75 x 10^24 molecules of CO2 is equivalent to approximately 6.24 moles.
211g of carbon dioxide are equal to 4,794 moles.