1 mol is equal to 6.02214179(30)×1023 molecules of the substance. The molecular weight is how much grams these molecules (6.02214179(30)×1023) weigh. Meaning g/mol.
The molar ratio of hydrogen to oxygen in the compound is 1:1. This means the compound is water (H2O), which has a molecular mass of 18.0 g/mol, not 34.0 g/mol. The given molecular mass of 34.0 g/mol does not match the properties of water.
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
The empirical formula CH2O has a molar mass of 30 g/mol (12 g/mol for C + 2 g/mol for H + 16 g/mol for O). To find the molecular formula, which is a multiple of the empirical formula, you divide the molar mass given (180 g/mol) by the empirical formula mass (30 g/mol), giving you 6. Therefore, the molecular formula for the compound is (CH2O)6, which simplifies to C6H12O6, the molecular formula for glucose.
The molar ratio of hydrogen to oxygen in the compound is 2:1. To find the empirical formula, divide the moles of each element by the smallest number of moles, which is 0.059 mol for hydrogen. This gives a ratio of 1:0.5 for hydrogen and oxygen, which simplifies to the empirical formula H2O. To find the molecular formula, calculate the molecular mass of H2O (18 g/mol) and divide the given molecular mass (34 g/mol) by the empirical formula mass to get the multiplier of 2. So, the molecular formula of the compound is H2O2.
1 mol is equal to 6.02214179(30)×1023 molecules of the substance. The molecular weight is how much grams these molecules (6.02214179(30)×1023) weigh. Meaning g/mol.
The molar ratio of hydrogen to oxygen in the compound is 1:1. This means the compound is water (H2O), which has a molecular mass of 18.0 g/mol, not 34.0 g/mol. The given molecular mass of 34.0 g/mol does not match the properties of water.
4.51 g x 1 mol x 6.022 x 1023 molecules = 9.95 x 1021 molecules .............273 g ............... 1 mol
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
There are 1.52 x 10^24 molecules of CH4 in 2.52 mol of CH4.
The empirical formula CH2O has a molar mass of 30 g/mol (12 g/mol for C + 2 g/mol for H + 16 g/mol for O). To find the molecular formula, which is a multiple of the empirical formula, you divide the molar mass given (180 g/mol) by the empirical formula mass (30 g/mol), giving you 6. Therefore, the molecular formula for the compound is (CH2O)6, which simplifies to C6H12O6, the molecular formula for glucose.
The molar ratio of hydrogen to oxygen in the compound is 2:1. To find the empirical formula, divide the moles of each element by the smallest number of moles, which is 0.059 mol for hydrogen. This gives a ratio of 1:0.5 for hydrogen and oxygen, which simplifies to the empirical formula H2O. To find the molecular formula, calculate the molecular mass of H2O (18 g/mol) and divide the given molecular mass (34 g/mol) by the empirical formula mass to get the multiplier of 2. So, the molecular formula of the compound is H2O2.
The molecular mass of an aldehyde depends on the specific compound. For example, the molecular mass of formaldehyde (CH2O) is 30.03 g/mol, while the molecular mass of acetaldehyde (C2H4O) is 44.05 g/mol. You can calculate the molecular mass by adding up the atomic masses of all the atoms in the compound.
The molecular formula of the compound is C2H4, which has a molar mass of 28 g/mol. Since the given compound has a molar mass of 42.0 g/mol, it must include an additional CH2 group, resulting in the molecular formula C2H6.
20g of N2 has more molecules because nitrogen (N2) has a smaller molar mass (28.02 g/mol) compared to carbon monoxide (CO) which has a molar mass of 28.01 g/mol. This means that 20g of N2 contains more moles and, therefore, more molecules.
The molar mass of CH2 is 14 g/mol (carbon: 12 g/mol, hydrogen: 1 g/mol). To get a molar mass of 168 g/mol, we need to multiply CH2 by 12. The molecular formula for the compound with a molar mass of 168 g/mol would be C12H24.
The molecular weight of C60H122 is approximately 820.03 g/mol. This is calculated by adding the atomic weights of each carbon (12.01 g/mol) and hydrogen (1.01 g/mol) in the compound.