How many atoms of calcium are present in 60.8 g of calcium?

Answer 1

First you need to find how many moles of calcium that is. Since 1 mole of calcium is 40.078g you need to divide 60.8g by how much is one mole (60.8 / 40.078 = 1.517 moles). Once you know how many moles you have (1.517) you can find how many particles there are. There are 6.02 *10^23 atoms in one mole (Avagadro's number), so your final answer will be, 6.02*10^23 x 1.517 = 9.132 * 10^23

Answer 2

There are approximately 1.52 x 10^24 atoms of calcium present in 60.8 g of calcium. This calculation is based on Avogadro's number (6.022 x 10^23 atoms/mole) and the molar mass of calcium (40.08 g/mol).