There are 34 atoms in C16H12O6: 16 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.
Yes Neon has isotopes from 16-34.
In a molecule of H2O2, there are 2 protons and 2 electrons from the two hydrogen atoms, and 4 protons and 4 electrons from the two oxygen atoms, making a total of 6 protons and 6 electrons.
Approximately 2.5 moles of ATP are produced from each mole of NADH oxidized in the electron transport chain (ETC), while about 1.5 moles of ATP are produced from each mole of FADH2 oxidized in the ETC. This difference arises from the different redox potentials and positions of NADH and FADH2 in the electron transport chain.
68 divided by 2 is equal to 34. So, 34 goes into 68 2times.
There are 2 moles of hydrogen atoms in 1 mole of H2O2 because each molecule of H2O2 contains 2 hydrogen atoms.
To find the mass of nitrogen needed to make 34 g of ammonia, we first need to calculate the molar mass of ammonia (NH3), which is 17 g/mol. From this, we can see that 1 mole of ammonia contains 1 mole of nitrogen. Therefore, the mass of nitrogen needed would also be 34 g.
1 mole H2SO4 x 4 moles O/mole H2SO4 x 6.02x10^23 atoms of O/mole O = 2.4x10^34 oxygen atoms
There are 34 atoms in C16H12O6: 16 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.
To make 34 g of ammonia, you need 2 moles of nitrogen gas since the balanced chemical equation is 3H2 + N2 -> 2NH3. Therefore, you need (2 moles N2) x (28 g/mole) = 56 g of nitrogen gas.
34 moles of NaCl is equivalent to 1 986,95 g.
There are approx 2.05*1025 molecules.
To find the grams in 88.4 moles of NI3, you need to multiply the number of moles by the molar mass of NI3. The molar mass of NI3 is 381.6 g/mol. Therefore, 88.4 moles of NI3 is 88.4 moles x 381.6 g/mol = 33,707.04 grams of NI3.
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
5.0 grams gold (1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 1.5 X 1022 atoms of gold ===================
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
To determine the number of moles in 34 grams of KOH, we first need to calculate its molar mass. The molar mass of KOH is approximately 56.11 g/mol (potassium: 39.10 g/mol, oxygen: 16.00 g/mol, hydrogen: 1.01 g/mol). Divide the given mass by the molar mass to find the number of moles: 34 g / 56.11 g/mol ≈ 0.61 moles of KOH.