answersLogoWhite

0

A mole of any kind of chemical unit, by definition/calculation, contains Avogadro's Number of the chemical units. 3.4 X 6.022 X 1023 is about 2.0 X 1024 nitrogen atoms, to the justified number of significant digits.

User Avatar

Wiki User

12y ago

What else can I help you with?

Related Questions

How many mole of H atoms in 1 mole of H2O2?

17.32 moles H2O (2 moles H/1 mole H2O) = 34.64 moles hydrogen


What mass of nitrogen is needed to make 34 g of ammonia?

To find the mass of nitrogen needed to make 34 g of ammonia, we first need to calculate the molar mass of ammonia (NH3), which is 17 g/mol. From this, we can see that 1 mole of ammonia contains 1 mole of nitrogen. Therefore, the mass of nitrogen needed would also be 34 g.


How many O atoms are in 1 mole of H2SO4?

1 mole H2SO4 x 4 moles O/mole H2SO4 x 6.02x10^23 atoms of O/mole O = 2.4x10^34 oxygen atoms


How many atoms are in C16H12O6?

There are 34 atoms in C16H12O6: 16 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.


How many grams of nitrogen gas are needed to make 34 g of ammonia?

(34 g NH3) x (14 g N ) / (17 g NH3) = 28 g N(28 g N) x (1 g N) / (2 g N2) = 14 g N2


How many gram of 34M of NaCL?

34 moles of NaCl is equivalent to 1 986,95 g.


How many molecules of carbon dioxide gas are there in 34 moles?

There are approx 2.05*1025 molecules.


How many grams are in 88.4 moles of NI3?

The molar mass of nitrogen triiodide is 394,719 g.So 88 moles is equivalent to 34 735,272 g.This strange compound has the curious property to explode when it is irradiated with alpha particles.


How many atoms are there in 34 grams of lithium?

Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms


5.6 moles of gold contain how many atoms?

5.0 grams gold (1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 1.5 X 1022 atoms of gold ===================


How many moles of sodium hydroxide will react with 17 moles of sulfuric acid?

In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.


How many moles are present in 34 grams of KOH?

To determine the number of moles in 34 grams of KOH, we first need to calculate its molar mass. The molar mass of KOH is approximately 56.11 g/mol (potassium: 39.10 g/mol, oxygen: 16.00 g/mol, hydrogen: 1.01 g/mol). Divide the given mass by the molar mass to find the number of moles: 34 g / 56.11 g/mol ≈ 0.61 moles of KOH.