If the heater is RATED at 5kw and is DESIGNED for 240v, it will draw 20.8 amps if 240v is applied.
I say it this way because you probably will not have exactly 240v. You may have as little as 220v or as much as 250v and still successfully operate this heater. But the difference in voltages would give you different currents.
For USA, Canada and countries running a 60 Hz supply service...
In general practice you would connect this heater to a 30amp 2-pole breaker using #10 gauge wire.
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As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed.
Before you do any work yourself,
on electrical circuits, equipment or appliances,
always use a test meter to ensure the circuit is, in fact, de-energized.
IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOB
SAFELY AND COMPETENTLY
REFER THIS WORK TO QUALIFIED PROFESSIONALS.
The resistance of a 5.0 kW heat strip can be calculated using Ohm's Law (Resistance = Voltage^2 / Power). Assuming the heat strip operates at 240 volts, the resistance would be approximately 115.2 ohms.
To calculate the amperage, you can use the formula: Amps = Watts / Volts. In this case, a 400-watt heater cartridge at 240 volts would draw 1.67 amps.
To calculate the amperage draw, you need to know the voltage of the circuit where the 2500 watts appliance will be used. You can use the formula: Amps = Watts / Volts. For example, if it is a 120V circuit, the amperage draw would be 2500 watts / 120 volts = 20.83 amps.
To calculate the current draw, use the formula: Current (A) = Power (W) / (Voltage (V) * √3). Plugging in the values, we get Current = 30000W / (208V * √3) ≈ 78.7A. So, a 30KW strip heater operating at 208 volts 3-phase would draw approximately 78.7 amps.
To calculate the amperage, use the formula: Amps = Watts / Volts. In this case, it would be 2400 watts / 240 volts = 10 amps. Therefore, the water heater would draw 10 amps of current.
Watts = Volts times Amps. Therefore, if the voltage was 220 volts, the motor would draw 500 amps. If the voltage was 4,000 volts, the motor would draw 27.5 amps. The voltages for large powerful motors tend to be relatively high, for example in the 380 Volts to 11,500 Volts range.
The resistance of a 5.0 kW heat strip can be calculated using Ohm's Law (Resistance = Voltage^2 / Power). Assuming the heat strip operates at 240 volts, the resistance would be approximately 115.2 ohms.
To calculate the amperage, you can use the formula: Amps = Watts / Volts. In this case, a 400-watt heater cartridge at 240 volts would draw 1.67 amps.
To calculate the amperage draw, you need to know the voltage of the circuit where the 2500 watts appliance will be used. You can use the formula: Amps = Watts / Volts. For example, if it is a 120V circuit, the amperage draw would be 2500 watts / 120 volts = 20.83 amps.
You would need to use a #12 copper conductor to continuously draw 14 amps at 120 volts.
To calculate the current draw, use the formula: Current (A) = Power (W) / (Voltage (V) * √3). Plugging in the values, we get Current = 30000W / (208V * √3) ≈ 78.7A. So, a 30KW strip heater operating at 208 volts 3-phase would draw approximately 78.7 amps.
To calculate the amperage, use the formula: Amps = Watts / Volts. In this case, it would be 2400 watts / 240 volts = 10 amps. Therefore, the water heater would draw 10 amps of current.
To calculate the amperage, you can use the formula: Amps = Watts / Volts. In this case, 2400 watts divided by 12 volts equals 200 amps. So, 2400 watts at 12 volts would draw 200 amps of current.
To calculate the amperage draw, you can use the formula P = V x I, where P is the power in watts, V is the voltage in volts, and I is the current in amps. Given that the power is 1200 watts and voltage is 120 volts, you can rearrange the formula to solve for current. Therefore, I = P / V, so the amperage draw of the heater would be 10 amps.
To calculate the amperage, you can use the formula: Amperage = Power (watts) / Voltage (volts). In this case, for a 2.2kW kettle at 240 volts, the amperage would be 9.17 amps.
Assuming a typical lay-in fixture is around 40 watts, it would draw approximately 0.15 amps at 277 volts. It's always recommended to check the specific fixture's specifications for accurate information.
To find amps if watts and volts are known, use the formula; watts / volts = amps or 5000 / 240 = 20.83 amps