If the heater is RATED at 5kw and is DESIGNED for 240v, it will draw 20.8 amps if 240v is applied.
I say it this way because you probably will not have exactly 240v. You may have as little as 220v or as much as 250v and still successfully operate this heater. But the difference in voltages would give you different currents.
For USA, Canada and countries running a 60 Hz supply service...
In general practice you would connect this heater to a 30amp 2-pole breaker using #10 gauge wire.
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As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed.
Before you do any work yourself,
on electrical circuits, equipment or appliances,
always use a test meter to ensure the circuit is, in fact, de-energized.
IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOB
SAFELY AND COMPETENTLY
REFER THIS WORK TO QUALIFIED PROFESSIONALS.
Depends on the voltage. Wattage is Volts x Amps. Resistance (ohms) is Volts divided by Amps. So on a 120V circuit, it would draw 41.66 amps. To do that, it would need a resistance of 2.88 ohms. But on a 240V circuit, it would draw 20.83 amps. That would require a resistance of 11.52 ohms. Determine the circuit voltage, then use that to figure the amps, then use that result to calculate the resistance necessary.
The formula you are looking for is I = W/E.
To calculate the amperage draw, you need to know the voltage of the circuit where the 2500 watts appliance will be used. You can use the formula: Amps = Watts / Volts. For example, if it is a 120V circuit, the amperage draw would be 2500 watts / 120 volts = 20.83 amps.
To determine the amperage drawn by a 250-watt metal halide bulb, you can use the formula: Amps = Watts / Volts. Assuming the bulb operates on a standard voltage of 120 volts, it would draw approximately 2.08 amps (250 watts / 120 volts). If it operates at 240 volts, it would draw about 1.04 amps (250 watts / 240 volts). Always check the specific voltage rating for accurate calculations.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
Watts = Volts times Amps. Therefore, if the voltage was 220 volts, the motor would draw 500 amps. If the voltage was 4,000 volts, the motor would draw 27.5 amps. The voltages for large powerful motors tend to be relatively high, for example in the 380 Volts to 11,500 Volts range.
Depends on the voltage. Wattage is Volts x Amps. Resistance (ohms) is Volts divided by Amps. So on a 120V circuit, it would draw 41.66 amps. To do that, it would need a resistance of 2.88 ohms. But on a 240V circuit, it would draw 20.83 amps. That would require a resistance of 11.52 ohms. Determine the circuit voltage, then use that to figure the amps, then use that result to calculate the resistance necessary.
The formula you are looking for is I = W/E.
To calculate the amperage draw, you need to know the voltage of the circuit where the 2500 watts appliance will be used. You can use the formula: Amps = Watts / Volts. For example, if it is a 120V circuit, the amperage draw would be 2500 watts / 120 volts = 20.83 amps.
You would need to use a #12 copper conductor to continuously draw 14 amps at 120 volts.
To determine the amperage drawn by a 250-watt metal halide bulb, you can use the formula: Amps = Watts / Volts. Assuming the bulb operates on a standard voltage of 120 volts, it would draw approximately 2.08 amps (250 watts / 120 volts). If it operates at 240 volts, it would draw about 1.04 amps (250 watts / 240 volts). Always check the specific voltage rating for accurate calculations.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
To calculate the amp draw for a 3800-watt water heater at 240 volts, use the formula: Amps = Watts / Volts. Thus, the amp draw would be 3800 watts / 240 volts, which equals approximately 15.83 amps. Therefore, the water heater draws about 16 amps.
Watts = Amps x Volts for a resistive load like a water heater.
The formula you are looking for is I = W/E. Amps = Watts divided by Volts.
To determine the number of amps a 500-watt power inverter draws, you can use the formula: Amps = Watts / Volts. Assuming a common household voltage of 120 volts, a 500-watt inverter would draw approximately 4.17 amps (500 watts / 120 volts = 4.17 amps). If the voltage is different, the amp draw will vary accordingly.
To calculate the current draw in amps for a 48-watt LED light at 12 volts, you can use the formula: Amps = Watts / Volts. So, 48 watts / 12 volts equals 4 amps. Therefore, a 48-watt LED light at 12 volts draws 4 amps.