11 amps
Volts X Amps = Watts so if your dryer is plugged into a 120V circuit (common in U.S.) you would divide:
1875 Watts / 120 Volts = 15.6 Amps
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A 1875 watt hair dryer typically draws around 15.6 amps. This can be calculated by dividing the wattage of the hair dryer by the voltage of the outlet it is plugged into, which is usually 120 volts in North America.
It depends on current or voltage, neither of which was specified in the question. Please restate the question.
Watts is a unit of power (energy/time), and totally unrelated to degrees, whether you mean angular measurement, or temperature.
A typical household hair dryer requires around 1.5 to 2.0 kVA (kiloVolt-Amps) to operate. It's important to check the specific power requirements of your hair dryer, as this can vary depending on the model and brand.
Without knowing the wattage that the hair dryer is rated at an amperage can not be stated. If you find the wattage, use this equation to find the amperage. I = W/E, Amps = Watts/Volts.
Amps = Watts / (Volts x Power Factor). Now a hair dryer has a motor and a resistive heater so if we assume a PF = .8 the answer is: 1500 / 20 = 75 amps. Since it is unlikely that you have a 75 amp hair dryer you must mean 125 volts. The answer for that would be 1500 / 100 = 15 amps which is still high, but believable. If we assume a Power Factor of 1 and ignore the motor contribution to Power Factor we have 1500 / 125 = 12 amps.
In some parts of the world, an 1875 watt hair dryer can and does use 220 volts from a 220 volt outlet?
A 1875-watt hair dryer may not get as hot as a 1600-watt one due to differences in design, airflow, and temperature settings. Higher wattage typically translates to more power, but if the 1875-watt dryer has a more efficient motor or greater airflow, it may prioritize drying speed over maximum temperature. Additionally, features like multiple heat settings can affect the perceived heat output. Therefore, the actual temperature reached can vary based on these factors rather than just wattage alone.