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How do you find time of flight from initial velocity and an angle at which an object is thrown?
If you're willing to ignore the effect of air resistance, then the answer is as follows: The object's horizontal velocity remains constant (at least until it eventually hits the ground). The vertical component of the object's initial velocity ... call it V(i) ... is the (total initial velocity) multipled by the (sine of the initial angle above the horizontal). Beginning at the time of the toss, the magnitude of the vertical component of velocity is V = V(i) - 1/2gT2. T = number of seconds after the toss g = acceleration of gravity = approx 32 ft/sec2 or 9.8 m/sec2
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Is the path that a thrown objects follows?
The path that a thrown object follows is called a projectile path, which is determined by the initial velocity and angle of the throw. The object moves in a curved trajectory, influenced by gravity pulling it downward. The shape of this path is typically a parabolic curve.
A body can escape the gravitational pull of the earth if it is thrown up with a velocity of?
In order for a body to escape the gravitational pull of the Earth, it needs to be thrown up with an initial velocity equal to or greater than the escape velocity of around 11.2 km/s. This velocity allows the object to overcome the gravitational pull of the Earth and continue traveling away from it indefinitely.
An object is thrown vertically upwards from the top of a tower of height 39.2 meters reach the ground in 4 secons Find the velocity with which it is thrown upwards?
To find the initial velocity with which the object is thrown upwards, we can use the kinematic equation for vertical motion: ( v = u + at ), where ( v ) is the final velocity (0 m/s at the highest point), ( u ) is the initial velocity, ( a ) is the acceleration due to gravity (-9.81 m/s²), and ( t ) is the time taken to reach the highest point (half the total time to reach the ground, so 2 seconds in this case). Rearranging the equation to solve for ( u ), we get ( u = v - at ). Plugging in the values, we get ( u = 0 - (-9.81 m/s² * 2 s) = 19.62 m/s ). Therefore, the object was thrown upwards with an initial velocity of 19.62 m/s.
What is the acceleration of an object thrown 3.5 meters at 44 meters per second?
The acceleration of an object thrown vertically upwards can be calculated using the kinematic equation (v_f^2 = v_i^2 + 2a \cdot d), where (v_f) is the final velocity, (v_i) is the initial velocity, (a) is the acceleration, and (d) is the distance. Given that the object is thrown vertically upwards, the equation becomes (0 = (44 , \text{m/s})^2 + 2 \cdot a \cdot (-3.5 , \text{m})). Solving for (a), we find that the acceleration is approximately -104 m/s², which indicates that the object is accelerating downwards.
What is the impact velocity of a rock thrown horizontaly from a cilff?
The impact velocity of a rock thrown horizontal from a cliff depends on two things, the initial speed of the rock (vi) and the height of the cliff (h). The final velocity (impact velocity) is represented by vfFor this formula, air resistance is neglected, and acceleration due to gravity is assumed to be 9.8 m/s2. The acceleration is positive here because down is being treated as the positive direction. You will get the same result if you use negative 9.8 m/s2 and make the height negative. sqr() means square root.vf = sqr(19.6h + vi2)For example if the rock was thrown off a 3 meter high cliff at 20 m/s, the impact velocity would be sqr(19.6 x 3 + 202), which would be sqr(58.8 + 202), which would be 21.42 m/s.The angle relative to the ground is the inverse tangent of sqr(19.6h)/viwhich in this case is tan-1( sqr(19.6 x 3)/20), which is tan-1(7.67/20) which is 21.0 degrees.
What is the best way to analyze an object thrown into the air?
The best way to analyze an object thrown into the air is to use projectile motion equations to calculate its initial velocity, angle of projection, and other relevant parameters. By breaking down the motion into horizontal and vertical components, you can determine its trajectory, maximum height, range, and time of flight accurately. Additionally, considering air resistance if necessary can provide a more realistic analysis of the object's motion.
What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
Is the acceleration the same on an object that is drop or when its thrown?
No, the acceleration is not the same for an object that is dropped and an object that is thrown. When an object is dropped, it experiences a constant acceleration due to gravity. When an object is thrown, its acceleration can vary depending on factors such as the initial velocity and direction.
Can the initial velocity be different if the final velocity is 0?
Yes, it is possible for the initial velocity to be different from zero when the final velocity is zero. For example, an object could be thrown upwards and come to a stop at its highest point, where the final velocity would be zero.
Why do objects that are thrown follow a curved path?
Objects that are thrown follow a curved path due to the influence of gravity and the initial forward velocity given to the object. Gravity pulls the object downward, causing it to accelerate, while the initial forward velocity allows the object to travel horizontally. The combination of these two forces results in the object following a curved trajectory known as a parabola.
A ball is thrown horizontally from a window on the second floor of a building What is the vertical component of its initial velocity?
The vertical component of the initial velocity of the ball thrown horizontally from a window is zero. The ball's initial velocity in the vertical direction is influenced only by the force of gravity, not the horizontal throw.
Is acceleration greater when the object is thrown vertically or horizontally?
Acceleration is dependent on the initial velocity of how fast the object is leaving the projectile. The vertical acceleration is greater when the object is falling than when the object reaches the peak in height. However, if the object is thrown horizontally and there is no parabola in its shape then there is not as great of an acceleration.
Curved path of an object thrown or launched on or near the surface of a planet?
The curved path of an object thrown or launched on or near the surface of a planet is called a trajectory. This trajectory is influenced by gravity, air resistance, and the initial velocity of the object. The shape of the trajectory can be parabolic for objects thrown horizontally, or elliptical for objects thrown at an angle.
Initial velocity of a softball thrown at 30 mph?
30 mph!
How is gravity different for objects that freely fall down and those thrown upwards?
The gravity acting on a rising object and that on a falling object are the same when these objects are at the same height. What is different is that a rising object is decelerating by the force of gravity and the falling object is accelerating.
The motion of an object thrown at an angle is what motion?
The motion of an object thrown at an angle is a combination of both horizontal and vertical motion. The horizontal motion is constant and is controlled by the initial velocity in the x-direction. The vertical motion is influenced by gravity, causing the object to follow a curved path.
The motion of an object thrown at an angle is motion?
The motion of an object thrown at an angle is projectile motion. This type of motion involves the object following a curved path due to a combination of its initial velocity and the force of gravity acting upon it. The object moves both horizontally and vertically as it travels through the air.
