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To draw the Lewis structure for SCl2, start by noting that sulfur has 6 valence electrons and each chlorine atom contributes 7 valence electrons. Place the sulfur atom in the center and connect one chlorine atom to each side. Place lone pairs on the sulfur atom to satisfy its octet and then place lone pairs on the chlorine atoms to complete their octets. Double-check that all atoms have a full octet and that the formal charges are minimized.
The Lewis dot structure for sulfur dichloride starts with the S for sulfur. To the left and right of the S are dashes that lead to one Cl on each side. Finishing it, every non connected side of the chlorine atoms has two dots and the top and bottom of the sulfur atom has two dots.
Cl-O-S-O-Cl would be my best bet. That way the octet rule is obeyed and everything is fine!
That's wrong! there is a double bond on both the O's that connect to Sulfer. This molecule is a special exception to the octet rule. Remember, oxygen prefers two lone pairs and sulfur in the third period, allowing it to have MORE than eight electrons!!!
Cl - S - Cl
The above structure should have 4 pairs of electrons around each chlorine atom, 1 bonding and 3 lone pairs, and the sulfur atom has 4 pairs of electrons 2 bonding and 2 lone pairs.
See attached link for a picture.
Tricky but..
6 H's on outside, 2 C in middle, Br with four dots between the two C's and two of the H's. Then 1 C on the other side between a C and a H.
H H
\ \
:Br: : Br:
/ /
H-C- C-H
/ \
:C: H
/
H
The Lewis structure of S2Cl2 is Cl-S-S-Cl with 3 lone pairs around the Cl and two lone pairs around the S.
Sulfur has two pairs of unpaired electrons (4 unpaired electrons).
Each chlorine atom shares one pair of electrons with the sulfur atom, resulting in two S-Cl bonds.
To draw a Lewis structure for Be2+, start by writing the symbol for beryllium. Since Be2+ has a 2+ charge, it has lost two electrons. Place the two electrons as individual dots around the beryllium symbol, as there is no other atom bonded to it. The Lewis structure for Be2+ is simply Be with two dots around it.
Cl has 7 electrons. If you draw Cl^-, there are 8 electrons and a minus 1 charge. What do you want to draw? And what do you mean by "odd" electrons?
Valence electrons are used to draw Lewis structures of molecules and atoms. These electrons are the outermost electrons of an atom that participate in bonding.
To draw a Lewis structure of a molecule or atom, you would typically use symbols to represent the atoms and lines to represent the bonds between atoms. The number of valence electrons for each atom is also considered to determine how the atoms are connected in the structure. Additionally, lone pairs of electrons on atoms are shown to complete their octets and achieve stability.
To draw the Lewis structure for CO2, place the carbon atom in the center and the two oxygen atoms on either side. Carbon forms double bonds with each oxygen atom to satisfy the octet rule. The Lewis structure for CO2 will have a total of 16 valence electrons.