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Hey there. Ive typed up a couple to use as examples using the brown hair. You must take into account the recessive and dominant traits, as this could range your answer being different.

A phenotype is the result of a genotype, which is the result of 2 alleles. Say if both parents were HOMOZYGOUS for brown hair, with their genotype would be BB, BB. Use a trick called a punnet square to answer this;

_|B |B |

B|BB|BB| <-- not the best punnet square, but the top row shows the first parents

B|BB|BB| genotype (BB) and the side shows the second's. (BB) The cross of this

shows all the children will have brown hair, as inherited from each parent.

If the Mother had HOMOZYGOUS brown hair (BB), and the father had HETEROZYGOUS brown hair (Bb) the results would be 100% Brown hair too, because the brown hair gene (B) is dominant over the non brown hair gene (b). Below;

_|B |B |

B|BB|BB| <--- this shows the cross gives a 50% chance to be Homozygous for brown

b|Bb|Bb| hair but 50% heterozygous for brown hair, but carrying a non- brown hair

gene.

If we cross 2 heterozygous parents, the results are shown:

_|B |b |

B|BB|Bb|

b|bB|bb| <----- This shows the child has a 75% chance of having brown hair (either

(BB or bB, Bb) and 25% of being non-brown (bb)).

This can be used in any gene cross, but you must keep in mind that one gene will be dominant and one will be recessive. I used the brown hair gene as an example here, as I don't know whether it may be dominant or recessive to other hair colours.

Also, if you were after a global statistic, I wouldn't know. I hope this helps you.

Fletch

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14y ago
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13y ago

For a punnet square counting only one trait:

Count all of the ones that have a capital letter. This is the number with the dominant phenotype. All of the ones with both lowercase letters are the recessive phenotype.

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14y ago

The Genotypic ratio of Dihybrid cross is 1:2:2:4:1:2:1:2:1

this ratio also called as dihybrid ratio.

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6mo ago

In a dihybrid cross involving two heterozygous parents (AaBb x AaBb), the genotypic ratio is 1:2:2:4 for the possible combinations of genotypes AA, Aa, BB, Bb in the offspring.

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9y ago

the phenotipic ratio is:

9:3:3:1

and i dnt know the genotipic!!

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11y ago

1 homozygous dominant: 2 heterozygous: 1 homozygous recessive

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12y ago

1:2:2:4:1:2:1:2:1

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13y ago

9:3:3:1

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12y ago

1:2:1

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Q: Genotypic ratio of a dihybrid cross?
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What is the expected genotypic ratios for di-hybrid cross and mono-hybrid cross?

In a dihybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively. In a monohybrid cross, the expected genotypic ratio is 1:2:1 for homozygous dominant: heterozygous: homozygous recessive genotypes, respectively.


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What is a mendelian ratio?

A Mendelian ratio is a ratio that describes the expected outcome of a genetic cross between two individuals for a particular trait, based on Mendel's principles of inheritance. For example, a 3:1 Mendelian ratio would indicate that in a monohybrid cross involving a dominant and recessive allele, approximately 75% of the offspring would exhibit the dominant trait and 25% would exhibit the recessive trait.


The phenotypic ratio resulting from a dihybrid cross showing independent assortment is expected to be what?

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Is RR X Dd a dihybrid cross?

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Rr x Rr is an example of what type of cross?

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