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Why normality of naoh is decrease?

Normality of NaOH = molarity of OH- , so for pure NaOH they are equal.When kept in open air the OH- ions come in contact with the slightly (and slowly) soluble carbon dioxide (CO2), which is an ACID forming oxide, thus reacting with the strong base hydroxide:CO2 + H2O -->H2CO3immediately followed by:H2CO3 + OH- --> HCO3-and eventually followed by a second step:HCO3- + OH- --> CO32-While hydroxide is 'disappearing' from solution, it decreases 'its' normality (= concentration of ions, reactive to acids)


When NaH is added to water the hydroxide concentration increases what can you include about NaOH?

The premise of this question is incorrect. When NaOH is added to water the hydroxide concentration increases. NaOH is a base. If a substance decreases hydroxide concentration it would be an acid.


What volume of NaOH was used in the titration?

To determine the volume of NaOH used in the titration, you need to know the concentration of the NaOH solution and the volume required to reach the endpoint. Use the formula: volume NaOH (L) = volume HCl (L) * concentration HCl / concentration NaOH.


How does failing to rinse down the unknown acid solution from the inside wall of the flask near the end of the titration affect concentration of NaoH?

Failing to rinse down the unknown acid solution from the inside wall of the flask near the end of the titration can lead to a false indication of excess NaOH titrant. This can result in an inaccurate calculation of the concentration of NaOH in the solution, leading to a higher reported concentration. Inaccurate rinsing can also affect the consistency and reproducibility of experimental results.


When NaOH is diluted to half of its original concentration what affect does this have on titration?

If NaOH is diluted to half of its original concentration, this would mean that the molarity has also been halved. During titration, this would result in requiring twice the volume of the diluted NaOH solution to reach the endpoint compared to the original concentration.


What is the effect of dilution on the pH of NaOH?

pH would decrease since H+ concentration increases, while pOH would increase since OH- concentration decreases. But pH would always be above 7 and pOH would always be below 7 since H+ will never be equal to OH- [OH-] would be always be greater than [H+] in any solution of NaOH , however dilute. Also remember pH + pOH =14, thus if pH decreases then pOH increases. Thanking you Yours Rajiv


Does HCl change in concentration when neutralized with NaOH?

Yes, when HCl is neutralized with NaOH, the concentration of HCl decreases as it reacts with NaOH to form water and NaCl. The concentration of the resulting NaCl solution will increase as the reaction progresses.


What is the concentration of 26 baume NaOH?

A 26 Baume NaOH solution has a concentration of approximately 30.9% NaOH by weight. The Baume scale is used to measure the density of a solution, with 26 Baume corresponding to this specific concentration of sodium hydroxide.


A solution is prepared by mixing 360.0 mL of 0.25 M NaOH with 140.0 mL of 0.50 M NaOH and the final concentration is?

The concentration is 12,8 g/L NaOH.


Why do we need to standardize the NaOH solution?

Standardizing the NaOH solution is important to ensure its accuracy and consistency in chemical reactions and experiments. This process helps determine the exact concentration of the solution, allowing for precise and reliable results in scientific research and analysis.


Why is it necessary to standardize the NaOH solution before titration?

Standardizing the NaOH solution before titration is important to accurately determine its actual concentration. This ensures the accuracy and reliability of the titration results by eliminating any discrepancies that may arise from variations in the concentration of the NaOH solution.


How do you calculate of NaOH in solution procedure?

To calculate the concentration of NaOH in a solution, you would typically measure the volume of the solution and the amount of NaOH used to prepare it. Then, you can use the formula: Concentration (in mol/L) = amount of NaOH (in mol) / volume of solution (in L) to determine the concentration. Make sure to convert any given amount of NaOH from grams to moles before calculating.