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∙ 14y agoThe phenotypic ratio will be 1:3.his son will be color blind.
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∙ 14y agoThe expected phenotypic ratio for their offspring is 1:1, with a 50% chance of being color blind (male with the X-linked recessive trait) and a 50% chance of having normal color vision. This is because the daughter is a carrier of the recessive allele, which can be passed on to her offspring regardless of the father's color vision status.
If the father carries the gene for color blindness on his X chromosome and the mother is a carrier of the gene, there is a 50% chance that their daughter could inherit the gene for color blindness and be affected. The daughter would need to inherit the X chromosome carrying the gene from both parents to have color blindness.
No, if the woman does not carry the recessive allele for color blindness, their children will not inherit the color blind allele from her. Since color blindness is a recessive trait, both parents must carry the allele for their children to be carriers.
Yes. A person is color blind if all his or her X chromosomes have the defective gene. A man have one X chromosome, and a woman has two. Thus: If only the father is color blind - The probability that the son is color blind is 0% - The probability that the daughter is color blind is 0% - The probability that the daughter is a bearer of the defective gene is 100% If the mother is a bearer of the defective gene, but is not color blind, and the father is not color blind - The probability that the son is color blind is 50% - The probability that the daughter is color blind is 0% - The probability that the daughter is a bearer of the defective gene is 50% If the mother is a bearer of the defective gene but not color blind, and the father is color blind - The probability that the son is color blind is 50% - The probability that the daughter is color blind is 50% - The probability that the daughter is a bearer of the defective gene is 100% If the mother is color blind and the father is not - The probability that the son is color blind is 100% - The probability that the daughter is color blind is 0% - The probability that the daughter is a bearer of the defective gene is 100% If both parents are color blind - The probability that the child, regardless of gender, is color blind is 100%
All daughters will be carriers of the red-green color blindness gene, but none will exhibit the trait. This is because the gene is carried on the X chromosome and daughters will inherit one X chromosome from both parents.
Type 'O' blood is a recessive factor, which means that it can't be hiding anymore recessive factors hiding so no its not impossible.
There is no chance for a colorblind daughter because the x-chromosome that comes from the male is normal and then it does not matter which x-chromosome comes from the female because colorblindness is a recessive gene, therefore there is no chance.
It all will depend on what kind of (recessive or dominant) alleles are responsible for the colorblind characteristic and what kind of alleles do the parental genes have.
Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.
Each gamete has a 50% chance of inheriting the allele for color blindness because the mother is heterozygous for the trait.
The father has to be colorblind for the daughter to be colorblind because both X chromosomes must have the colorblindness gene in females because the colorblind gene is recessive. If only the mother is color deficient, then she merely passes on the gene to one of the X chromosomes in a female. If both the mother and father are both colorblind, then both X chromosomes in the female are effected and the female is colorblind. There are two scenarios in which a daughter may be born colorblind. 1. The father is colorblind and the mother is a carrier of the colorblind gene. The daughter will be either colorblind or a carrier of the colorblind gene. 2. The father and mother are both colorblind. If this is the case, then all of the children will be born colorblind.
If the father carries the gene for color blindness on his X chromosome and the mother is a carrier of the gene, there is a 50% chance that their daughter could inherit the gene for color blindness and be affected. The daughter would need to inherit the X chromosome carrying the gene from both parents to have color blindness.
the colorblindness is usually not activited in a female body but is usually seen in male
For a couple to have a color-blind daughter, both parents must carry the recessive gene for color blindness. The mother would need to be a carrier with the genotype X^BX^b, and the father would need to have the genotype X^bY. This gives a 25% chance of their daughter inheriting the X^bX^b genotype and being color-blind.
No, if the woman does not carry the recessive allele for color blindness, their children will not inherit the color blind allele from her. Since color blindness is a recessive trait, both parents must carry the allele for their children to be carriers.
It depends on a number of different factors. If colorblind is common in either family but the mother/father were lucky enough not to get it, then its a recessive gene. but if its not common in either family then its a very low chance the child will be color blind. Although, if there are numerous people on both sides of the family the probability is very high. It all depends on a lot of different factors. How dominant is the gene? How many relatives are colorblind? If there are any, and they have children, are they colorblind? The easiest way to figure out if the child will be colorblind is to have the kid and test it for colorblind-ness.
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
Colorblindness is not typically considered a disability, as it does not significantly limit a person's ability to perform daily tasks or participate in activities. However, it may pose challenges in certain situations, such as distinguishing between colors, but it does not normally impede someone from leading a full and productive life.