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A 21.2 kg child descends a slide 3.5 m high and reaches the bottom with a speed of 2.1 ms How much thermal energy due to friction was generated in this process?
Wiki User
∙ 14y ago
The potential energy he lost on the descent = M g H = (21.2) (9.8) (3.5) = 727.16 joules
The kinetic energy he had at the bottom = 1/2 M V2 = (0.5) (21.2) (2.1)2 = 46.746 joules
The missing energy = (727.16 - 46.746) = 680.414 joules caused heating of the slide and the kid's pants.
Wiki User
∙ 14y ago
To find the thermal energy due to friction, we first calculate the initial potential energy of the child at the top of the slide which is given by mgh = 21.2 kg * 9.81 m/s^2 * 3.5 m. Next, we calculate the final kinetic energy at the bottom using KE = 0.5 * m * v^2 = 0.5 * 21.2 kg * (2.1 m/s)^2. The difference between the initial potential energy and final kinetic energy is the thermal energy lost to friction during the slide.
Wiki User
∙ 8y agoUse conservation of energy to solve this one. Calculate the gravitational potential energy at the top, and the kinetic energy at the bottom. The difference has been lost to friction, i.e., converted to thermal energy.
Wiki User
∙ 7y agoThe answer depends on the coefficient of friction between the child's clothing and the slide as well as the speed with which the child reaches the bottom of the slide.
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