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Simply put, 1.6 Amps, or for that matter any number of Amps (which is current), has nothing in and of itself, to do with Watts (which is power).

In any circuit, there are three fundamental units of electrical properties - voltage (E), current (A), and resistance (R). In addition, there's the related unit of power (which are Watts[W]). In any circuit, knowing any two of the four will allow determining the third and forth. The fundamental rule used is called "Ohm's law" which states that the voltage across any circuit is proportional to it's resistance, and the current through it and is usually written as:

E = I x R or simply E = IR

One important detail is that V is commonly used instead of E. So E = I x R is the same as V = I x R. But using "E" is more proper (and stands for the formal name for voltage, "electromotive force" also sometimes abbreviated as "EMF").

One other essential equation is W = I x E.

Using these two equations will answer your question but you must have at least one more unit in addition to Amps, either power, resistance, or voltage.

Without knowing another unit in addition to your current of 1.6A, the question cannot be answered.

As an example, let's take a 100W light bulb which runs on 120V.

Using the relationships shown above, we can calculate that for this bulb, it's current is I = W / E = 100W / 120V = 0.833A.

It's resistance then, is E / I = 120V / 0.833A = 144 Ohms.

So given it's power (W) and voltage (E) we have all four quantities:

E = 120 Volts, R = 144 Ohms, I = 0.8 Amps, W = 100 Watts

Note that combining and rearranging the two equations for E & W (this requires pretty basic algebra and won't be detailed here. Just the equivalent equations will be shown), it can be shown that any two values can be used to derive all four. All the combinations are thus:

Given I and W:

E = W / I = 100W / 0.833 Amps = 120V and,

R = W / I^2 = 100W / 0.833^2 = 144 Ohms

Given R and W:

E = SQRT(W x R) = SQRT(100 x 144) = 120V and,

I = SQRT(W / R) = SQRT(100 / 144) = 0.8333A

Given E and R:

W = E^2 / R = 14400 / 144 = 100W and,

I = E / R = 120 / 144 = 0.8333A

Given E and I:

W = E x I = 120 x 0.8333 = 100 Watts and,

R = E / I = 120 / 0.8333 = 144 Ohms

Given I and R:

E = I x R = 0.8333 x 144 = 120V and,

W = I^2 x R = 0.6944 x 144 = 100 Watts

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8y ago
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11y ago

Now we cannot equate watt to ampere. Watt is unit of power where as ampere is the unit of current. Power is got by the product of voltage and current.

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12y ago

That depends on what the circuit voltage is. 1 watt is equal to 1 volt times 1 amp.

So if the system voltage is 12 volts , times 1.6 amps, you have 19.2 watts.

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8y ago

In a car electrical system, using 12 volts.
P = I x V, P = 1.6 x 12 = 19.2 watts

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