True
beacause it is my hobby
Although you don't list the composers from whom you want us to choose, the name you require is Leonard Bernstein. (The lyrics were written by Stephen Sondheim.)
SchubertWhat are the choices? You say "which" but don't give any names to choose from.
Many professionals will own one good instrument. Sometimes, if they own two, one will be used for certain pieces. Each instrument sounds different, so depending on the sound they want to deliver for each piece, they choose the instrument they want. There is not a difference.
True
he chose his instrument the trumpet because he wanted a brass instrument
The answer is 4,960.
10
beacause it is my hobby
There are 36 possible combinations.
There are 220 combinations. Do you want to know why this is the answer? (It's worth knowing because this is a widely used principle in mathematics.) There are 10 digits to choose from, four of them are to be chosen at a time and a combination of four can include more any given digit more than once. So the total number of 4-digit combinations (without insisting that there be any 2s in them) is (10+4-1)choose 4= 13 choose 4 = 715. If 2s are _not_ allowed then there would be 9 digits to choose from and the total number of 4-digit combinations would be (9+4-1) choose 4 = 12 choose 4 = 495. Then the number of 4-digit combinations in which anywhere from 1 to 4 2s are allowed would be 715 - 495 = 220.
The number of 4 different book combinations you can choose from 6 books is;6C4 =6!/[4!(6-4)!] =15 combinations of 4 different books.
Although you don't list the composers from whom you want us to choose, the name you require is Leonard Bernstein. (The lyrics were written by Stephen Sondheim.)
If the order of the numbers are important, then this is a simple combination problem. There are 10 possible numbers to choose from for the first number. Then there are 9 options for the second number. Then there are 8 options for the third, and so on. Thus, the number of possible combinations can be calculated as 10x9x8x7x6x5. This comes out at 151,200 possible combinations.
Code Black offers a variety of combinations to choose from and each one is more gratifying
Formula: nPr where n is the number of things to choose from and you choose r of them 17P3 = 17!/ (17-3)! = 4080