Na and K are both alkali metals in group 1A of the periodic table.
Both of these elements do not handle oxygen well, and react violently when they come in contact with it.
Both Na and K can form +1 cations (Na+ and K+).
They can both be used to form salts when used in ionic acid-base reactions.
the similarity between sports and games are that there really entertaining, enjoyable and fun. you learn better.
The only similarity which I identified between these programs is of "HUMAN INTERACTION"
which of the following describes the similarity between the retained earning, and common stock account?
no
long
NaCl---------------→Na+ + Cl-
The cation, or positively charged ion, in NaCl is Na+.
The equation is: NaCl----------Na++ Cl-
In NaCl, the molar mass of Na is 22.99 g/mol and Cl is 35.45 g/mol. Therefore, the molar mass of NaCl is 58.44 g/mol. Given 8.0g of NaCl, the mass is distributed between Na and Cl in a 1:1 ratio. Thus, there are 3.5g of Na in 8.0g of NaCl.
Na+ + Cl- --> NaCl NaCl = salt.
An example is the dissociation of NaCl in water: NaCl (s) -> Na+ (aq) + Cl- (aq). Here, NaCl breaks apart into its constituent ions, Na+ and Cl-, when dissolved in water due to the attraction between the ions and water molecules.
NaCl --> Na+ + Cl- You could write water on either side I suppose, but it is negligible. I've also seen H2O written over the arrow.
no
NaCl is the formula unit of sodium chloride.
The molecular weight of NaCl is 58.44 g/mol. So in 348 grams of NaCl, you have 58.44% of it coming from sodium (Na), which is approximately 203.6 grams of sodium.
Since NaCl is composed of one Na atom and one Cl atom, and the molar mass of Na is roughly 23 g/mol while that of Cl is about 35.5 g/mol, the molar mass of NaCl is approximately 58.5 g/mol. In 100 ppm NaCl, there are 100 mg of NaCl in 1 kg of solution. Therefore, the amount of Na in 100 ppm NaCl would be 100 mg * (23 g Na / 58.5 g NaCl) = ~ 39.3 ppm Na.
No, a 100 ppm NaCl solution means there are 100 parts per million of NaCl (sodium chloride) in the solution, not just sodium (Na) alone. To calculate the amount of sodium ions (Na+) in the solution, you would need to consider the molar mass of NaCl and the percentage of Na+ in NaCl.