They are both hard like my boner.
No. Barium and magnesium and calcium are in group 2A but potassium is in group 1A.
6a to the second power minus 8ab + 2a
(2a + 1)(4a2 - 2a + 1)
Usually, the easiest way to do this is to find a pair of numbers whose sum is equal to the coefficient of the first term, and whose product is equal to the product of the coefficients of the first and last terms: a + b = -3 a * b = -10 take all possible pairs of numbers that multiply to make negative ten: 1 * -10 = -10 -1 * 10 = -10 2 * -5 = -10 -2 * 5 = -10 and then find which one of those pairs also adds up to negative three: 1 + (-10) = -9 -1 + 10 = 9 2 + (-5) = -3 -2 + 5 = 3 So 2 and -5 are the coefficients we want. Now take our original equation: 10a2 - 3a - 1 and separate the middle term into two terms using those coefficients: 10a2 - 5a + 2a - 1 You can then factor a common term out of the first pair and last pair of terms: 5a(2a - 1) + 1(2a - 1) and then group your coefficients: (5a + 1)(2a - 1) Giving you the answer.
If that's -10, the answer is (a + 5)(a - 2). If that's +10, it gets ugly in a hurry.
bilat
since a=1a, 3a-1a=2a
hydrogen
group 1a , group 2a , transition elements , group 0 (inert gases)
No. Barium and magnesium and calcium are in group 2A but potassium is in group 1A.
1a+3b 2a+4b=3a +7b
1
Metals in group 1A, 2A, 3A can form mono-, di- and trivalent positive ions respectively, and all are metals except Boron, which is a metalloid (between Carbon -a nonmetal- and Berillium -a metal- in period II).
2a - a = a
the group 1a has a positive charge which means it looses 1(-1) to become a noble gas and group 2a has positive 2 which means it looses 2(-2) to become a noble gas and so on
-1a
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