The parity (odd or even) of days depends on the number of days in a month - not the number of days in a week.
It is the twelfth month of the year and in that context is even. It has 31 days: in that context it is odd.
365 total days in a year/2= 183 odd days.
odd,185,even,184
183
The same as it does on even days of the year!
The parity (odd or even) of days depends on the number of days in a month - not the number of days in a week.
It is the twelfth month of the year and in that context is even. It has 31 days: in that context it is odd.
365 total days in a year/2= 183 odd days.
odd,185,even,184
In a non leap year, there are 7 months with an odd number of days, if we exclude those 7 days you would have the same number of even & odd days. The formula will be: (Total numbe of days - 7 ) / 2 = even number of days ( 365 - 7) / 2 = 179 Now you need to add back the days you excluded and you have the odd number of days. 179 + 7 = 186 In a leap year, you need to add one to that, so it is 187.
Assume that odd days refers to the number of the day in the year then in both a leap year and a non-leap year there are 183 odd days, totaling, for a decade, to 1830 odd days.
16 odd days and 15 even days.
There were 365 days in 1850.
183
i think monday wednsday friday are odd
there are 186 odd days if it is NOT a leap year.