Various types of rock are used as construction and landscaping materials. For example, crushed granite is a convenient and inexpensive material for paving driveways and garden paths. It is necessary on such projects to figure out the cubic yards of material needed, and rock is usually sold in cubic yards. A cubic yard is a measurement of volume, rather than area, and it tells you how much material is needed to fill a space, instead of just covering the surface.
Measure the length and width, in feet, of the area to be covered.
1 cubic yard of crushed rock fills 3/depth in feet square yards.
About 35... there are 27cubic feet in one cubic yard so determine how many cubic feet you need and divide by 27... in your case 52x 18x 1= 936 cubic feet 936/27= 34.66 cubic yards
38ft*6ft*1.5inch = 38/3 yards*2yards*1.5/36yards = 1.055... cubic yards.
Square footage is only PART of the equation. You also need to know the temperature of the ice you're trying to melt.
The answer will depend on the depth of the covering that is required. Without that information, the question cannot be answered.
You need to know the weight of 1 cub. yard of rock.
Unless the rock is completely flat, there is no point in measuring the rock in yards.
1
1 cubic yard of crushed rock fills 3/depth in feet square yards.
there is about 1.25 yards to a ton,so 22.5 tons would be approx 18 yards
They need to determine the amount of radioactive decay of a specific isotope in the rock since its formation.
For the calculus you need the density of this rock: M = V x d.
how much 1" rock will I need to fill in a hole 20' long, 2' wide' and about 2' deep
About 35... there are 27cubic feet in one cubic yard so determine how many cubic feet you need and divide by 27... in your case 52x 18x 1= 936 cubic feet 936/27= 34.66 cubic yards
Provided it's not a short tandem, 15 yards with a 'rock tub' dump body and 16 yards with a 'dirt tub' dump body are typical.
Almost 6 yards, or about a medium dump truck load.
This depends on how much rock you will use per square yard. Suppose you intend to use 1/100 tons (=20 lb) per square yard. Then if you have one ton of rock, it will cover 100 square yards. Similarly, if you intended to use 1/50 tons per square yard, 1 ton will cover 50 square yards. In general you want to use factor labeling: If you are using x tons per square yard, then write this as (1 square yard) / (x tons of rock) = (1/x)*(square yards/tons of rock) This is called a conversion factor. Now, if you have some quantity of rock, say y tons of rock, and you want to see how many square yards it would cover you just multiply (y tons of rock)*(1/x)*(square yards/tons of rock) = y/x (square yards*tons of rock/tons of rock) = y/x square yards since the labels just divide out.