What is The kinetic energy of a 25-gram bullet traveling at 500 ms?

Answer 1

Dear Wiki Questioner,

To calculate the kinetic energy of an object, we use the following equation:

KE=(1/2) m v^2

Where KE is the object's kinetic energy in Joules

m is the object's mass in kilograms

and v is the object's velocity in meters per second

So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation:

25g (1 kg/ 1000 g) = .025 kg

The mass of the bullet is .025 kilograms!

Now we plug the numbers into the equation and solve:

KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J

So the kinetic energy of your bullet is 3125 Joules