CH3COOH is a acid. It is a weak acid.
NaHCO3 is a weak base, with a conjugate acid of H2CO3+.
It is the product of a strong acid and a weak base, but is itself a mildly acidic salt.
If acid is strong then its conjugate base must be weak, if conjugate base is strong it again accept the H+ ions so acid can neither be strong, similarly if base is strong its conjugate acid must be weak.
The solution at the endpoint of an acid-base titration involving a weak acid and a strong base will be alkaline. This is because the weak acid will have been neutralized by the strong base, resulting in excess hydroxide ions in the solution causing it to be alkaline.
b) The conjugate acid of a weak base is a weak acid. When a base accepts a proton to form its conjugate acid, it tends to be a weak acid because it does not easily donate a proton back. This relationship is governed by the principles of acid-base equilibrium.
Acetic acid (CH3COOH) is a weak acid and sodium hydroxide (NaOH) is a strong base.
When a weak acid and a strong base combine, the resulting solution will be basic because the strong base will completely neutralize the weak acid. The pH of the solution will be higher than 7.
CoCO3 (Cobalt II carbonate) would be a weak base.
NH3 is a weak base, but H2CO3 ( carbonic acid ) is not a strong acid. It is a weak acid.
it is a non electrolyte C2H5OH is not a base, its an alcohol, ETHYL ALCOHOL so its just an alcohol
A weak acid can be neutralized effectively by adding a strong base to it. The strong base will react with the weak acid to form water and a salt, which will result in the neutralization of the acid.
No. CH3COOH is a weak acid known as acetic acid or ethanoic acid.