Where did General Johnston surrender to General Sherman?

Answer 1

The surrender of General Joseph E. Johnston's Confederate Army to General William T. Sherman at the Bennett Place, Raleigh, North Carolina, in April 26, 1865. It was the second and last major stage in the peace making process which ended the War Between the States. General Lee's surrender at Appomattox 17 days earlier was the first. The capitulation of General Richard A. Taylor's small force in Alabama a week later and of Kirby Smith's Trans-Mississippi Army at New Orleans exactly a month later concluded the process.

Johnston surrendered by far the largest share of the Confederate troops still in the field at war's end, more than Lee and the others combined. He surrendered all Confederate forces in the Carolinas, Georgia, and Florida and took those States out of the war.

General William T. Sherman advanced into North Carolina in early March, 1865, and moved toward Goldsboro, where supplies and additional troops awaited him. His desire was to pass through the State as quickly as possible and unite with General Grant in Virginia. He knew, however, that Johnston would try to block his advance. The attempt came at Bentonville, about 18 miles southwest of Goldsboro. Unable to stop the advance Johnston retreated to Smithfield and from there observed the enemy to determine which route would be taken for the eventual march north.

Meanwhile Sherman, unchecked but needing reinforcements, continued to Goldsboro where his army remained encamped until April 10. Sherman used this interlude to confer with Grant and President Lincoln in Virginia.