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How do you get a tan on animal crosssing?
You cant get a tan on animal crossing.
Are there people who cant tan?
Yes
What is knowledge connections for the word significant?
sign,cant,can,tan,
What adaptations to crabs have related to light intensity?
they cant tan but if they do they will turn purple
What do you do if you traded your opuntia fruit?
if you traded your fruit tan you cant finesh nabooti island
Why cant i level up higher tan 25 on pokemon power defense?
because you don't have a life
Why is Marilyn Manson's skin pale white?
1.) ....probably because he cant tan very well like some people (one of them being me, im very pale and cant help it) 2.) He's trying to make a statement? if you know Marilyn Manson, you know he's all about being himself. This question is like asking why someone is tan. Because they either 1. cant help it, or 2. felt like being tan.
How do you find the tangent of a triangle?
that queation doesnt make any sence u retard because u cant get the tan of a triangle u can only get the tan of a number To find the tan of an angle you want to use this ratio: Opposite side divided by adjacent side Once you find the answer, on a scientific calculator you enter in your answer and hit the inv button then the tan button and it should give you your answer.
Tan 9 plus tan 81 -tan 27-tan 63?
tan(9) + tan(81) - tan(27) - tan(63) = 4
What is a antonym of pale?
Tan Tan
What does por Que tan jodidamente mean?
"Por qué tan jodidamente" roughly translates to "why so fucking." It is an expression used to convey strong emotion or emphasis, often expressing frustration, anger, or astonishment.
If for a triangle abc tan a-b plus tan b-c plus tan c-a equals 0 then what can you say about the triangle?
tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).
