I think that the relation is R = k/L where R is the resistance, L is the length of the wire, and k is the constant of proportionality.
when length is increased insulation resistance of cable is decresed i.e.,R is inversely proportional to L where R is resistance L is length
Cell constant(C) = Resistance(R) X Specific Conductivity(K)
The wire resistance is proportional to the length of wire divided by its cross-section area. The voltage drop is proportional to the resistance times the current.
There is a direct relationship between the length of wire (thus the number of times the wire is wrapped) and the electrical resistance of the guitar pickup, measured at the two output terminals.
This means that as the length of the extension cord increases, the resistance also increases. Similarly, if the length decreases, the resistance will decrease as well. This relationship is described by the equation R = kL, where R is the resistance, L is the length, and k is a constant.
There is no relationship. Knowing the length of one of them doesn't tell you the length of the other one.
They are just dating.
The radius is excatly half of the diameter
The length of one arm is about 40% of your height
In simple MOSFET current mirror, the load current does not follow a linear relationship with reference current (ie for short channel MOSFET's multiplying factor due to channel length modulation cannot be neglected). But by cascoding the output resistance can be increased and since output resistance follows an inverse relationship with lambda (channel-length modulation parameter), the multiplying factor due to channel length modulation reduces to one and a linear relationship is obtained between reference and load current.
Double the length is double the resistance. Resistance of a wire is the resistivity of the material, times the length, divided by the cross-section area.
The area of a square is the square of its side length.