(a2+2b2-2ab)(a2+2b2+2ab)
24a + b2 + 3a + 2b2= 27a + 3b2
do you mean 12a3 - 5a2b - 2b2 ?? = 12a3 + 8a2b - 3a2b - 2b2 then group 1st 2 terms and last 2 and use GCF = (12a3 + 8a2b) + ( - 3a2b - 2b2) = 4a2(3a + 2b) + (-b)(3a2 +2b) not much help, but that's all folks
We can combine the like terms. So the b2 can be combined with the 2b2 to give 3b2. Likewise the 3b plus the -5b gives -2b.Therefore, b2 + 3b - 5b + 2b2 = 3b2 - 2b.
2b2 + 8 para b = -3
n nn n
3a2b(2b2-1)
= 4a2 + 2ab 2b2
3(2b2 - 5b - 2)
11(2b2 + 21)
C. 12b3
The Answer to this question is 9 (2B+4) and (1B+3)