NaBr is a strong electrolyte because it dissociates completely in water into its constituent ions, sodium (Na+) and bromide (Br-) ions. This allows it to conduct electricity well in solution.
To find the grams of NaBr, first calculate the moles of NaBr using the molarity formula: Molarity (M) = moles of solute / liters of solution. Then convert moles to grams using the molar mass of NaBr (102.89 g/mol). In this case, 75.0 mL is 0.075 L. So, moles of NaBr = 1.5 mol/L * 0.075 L = 0.1125 moles. Finally, grams of NaBr = 0.1125 moles * 102.89 g/mol = 11.57 grams.
The melting point of NaBr is 747 oC.
NaBr has two elements: sodium (Na) and bromine (Br).
The chemical symbol for sodium bromide is NaBr.
No, NaBr is not an acid. It is the chemical formula for sodium bromide, which is a salt composed of sodium cations (Na+) and bromide anions (Br-).
NaBr is a salt composed of sodium (Na+) cations and bromide (Br-) anions. It is neither an acid nor a base.
2 Na + Br2 --> 2 NaBr
One formula unit of NaBr contains one sodium atom and one bromine atom, therefore NaBr has a total of 2 atoms.
The percent composition of bromine in NaBr is approximately 77.7%. This is calculated by dividing the molar mass of bromine by the molar mass of NaBr and then multiplying by 100.
To find the mass of NaBr in the mixture, we first calculate the mass of Na in NaCl and NaBr combined, which is 0.76 g. Since NaCl contains one Na atom and NaBr contains one Na atom, this entire mass comes from Na in NaCl and NaBr. Therefore, the mass of NaCl is 0.76 g and the remaining mass of the mixture (2.03 g - 0.76 g = 1.27 g) is due to NaBr.
The binary ionic compound name for NaBr is sodium bromide.