NaBR is sodium bromide. It is a high-melting white, crystalline solid that resembles sodium chloride and it is an electrolyte.
NaBr is a strong electrolyte because it dissociates completely in water into its constituent ions, sodium (Na+) and bromide (Br-) ions. This allows it to conduct electricity well in solution.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
The melting point of NaBr is 747 oC.
Sodium and bromine are the elements in sodium bromide (NaBr) compound.
The chemical symbol for sodium bromide is NaBr.
NaBr is a salt composed of sodium (Na+) cations and bromide (Br-) anions. It is neither an acid nor a base.
No, NaBr is not an acid. It is the chemical formula for sodium bromide, which is a salt composed of sodium cations (Na+) and bromide anions (Br-).
2 Na + Br2 --> 2 NaBr
A formula unit of NaBr contains 2 atoms: 1 sodium and 1 bromine.
The percent composition of bromine in NaBr is approximately 77.7%. This is calculated by dividing the molar mass of bromine by the molar mass of NaBr and then multiplying by 100.
To find the mass of NaBr in the mixture, we first calculate the mass of Na in NaCl and NaBr combined, which is 0.76 g. Since NaCl contains one Na atom and NaBr contains one Na atom, this entire mass comes from Na in NaCl and NaBr. Therefore, the mass of NaCl is 0.76 g and the remaining mass of the mixture (2.03 g - 0.76 g = 1.27 g) is due to NaBr.
The binary ionic compound name for NaBr is sodium bromide.