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You can,but you'll die. :(

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12y ago

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To neutralize the 0.10 M HCl in 25 mL, we first calculate the moles of HCl present: 0.10 mol/L * 0.025 L = 0.0025 mol HCl. Since 1 mole of HCl reacts with 2 moles of Mg(OH)2 (according to the balanced chemical equation), we need 0.0050 moles of Mg(OH)2. The molar mass of Mg(OH)2 is 58.3 g/mol, so we need 0.0050 mol * 58.3 g/mol ≈ 0.29 grams of Mg(OH)2.


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What is the mass of HCl that would be required to completely react with 5.2 grams of Mg?

The balanced chemical equation for the reaction between HCl and Mg is: Mg + 2HCl -> MgCl2 + H2. One mole of Mg reacts with 2 moles of HCl. Calculate the moles of Mg in 5.2 grams using the molar mass of Mg. Then use the mole ratio to find the moles of HCl needed, and finally calculate the mass of HCl using its molar mass.


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