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The genotype would have to be homozygous recessive if the child was completely effected by the disease. The "normal" paretns would have to have heterozygous recessive genotypes. This makes sense since the allele that causes sickle cell shows incomplete dominance when present with a normal allele in a pair. The "normal" parents actually would have a mixture of sickle cell shaped red blood cells combined with normal shaped ones. The carrier parents does not display symptoms of the disease since the regular red blood cells alone can fill the body's need for oxygen under normal circumstances. The only time the cArrier would notice would be under times of extreme oxygen demand, such as a sprint.
What else can I help you with?
What is the genotype of woman with cystic fibrosis?
A woman with cystic fibrosis has a genotype that includes two copies of the mutated CFTR gene, which is located on chromosome 7. This means she is homozygous for the CFTR mutation, typically represented as "ff" where "f" indicates the presence of the cystic fibrosis allele. In cases where she has one normal CFTR allele and one mutated allele, she would be considered a carrier but would not exhibit symptoms of the disease. However, those with cystic fibrosis must have two copies of the mutated gene.
Two parents who were phenotypically normal had to children The oldest was also phenotypically normal but the younger child had cystic fibrosis what is happening in the cross?
Cystic fibrosis is an autosomal recessive genetic disorder, meaning that a child must inherit two copies of the mutated gene (one from each parent) to express the condition. In this scenario, both parents are likely carriers of the cystic fibrosis allele (genotype Cc), where "C" is the normal allele and "c" is the mutated allele. The older child is phenotypically normal, which could mean they are either homozygous dominant (CC) or a carrier (Cc), while the younger child inherited two copies of the mutated allele (cc) from both parents, resulting in cystic fibrosis. This cross illustrates Mendelian inheritance patterns, where two carrier parents can have a child with a recessive condition.
What are the chances of a normal person and a carrier for cystic fibrosis have a kid with cystic fibrosis?
Zero. Cystic fibrosis is an autosomal recessive disease. This means that both parents must carry a mutated gene and have a 1 in 4 (25%) chance of having a child with CF.
Why can Cystic fibrosis be inherited even if neither parent has the disease?
Cystic Fibrosis is an example of a disease inherited as an autosomal recessive genetic disorder. Both parents of a baby who has Cystic Fibrosis have one abnormal recessive gene and one normal dominant gene and are therefore, Cystic Fibrosis carriers. Carriers are said to be heterozygous because they contain one normal copy of the gene and one abnormal copy. A baby who inherits cystic fibrosis has inherited the abnormal gene from both parents and is therefore said to be homozygous recessive.
When C equals normal allele and c equals allele for cystic fibrosis Set up and complete a Punnett Square for cystic fibrosis for a couple that both have heterozygous for cystic fibrosis with no sympt?
Sure! When both parents are heterozygous carriers (Cc) for cystic fibrosis, the Punnett Square would result in a 25% chance of having a child with cystic fibrosis (cc), a 50% chance of having a child who is a carrier (Cc), and a 25% chance of having a child who is not a carrier and does not have the disease (CC).
A couple who are both carriers of the gene for cystic fibrosis have two children who have cystic fibrosis What is the probability that their next child will be phenotypically normal?
If both parents are carriers on cystic fibrosis, just because two children may have the disease it doesn't mean that say,a further 3 children in future will be "normal". Inheriting genes is like a lottery. I can say though that because cystic fibrosis is recessive, every offspring born under carriers will always have a 75% chance of being phenotypically normal.
What would a genetic counselor tell parents who had cystic fibrosis or were carries of the cystic fibrosis about the chances of their children having cystic fibrosis?
If both parents are carriers then the child has a 25% chance of having cystic fibrosis. If one parent has CF and the other the other was just a carrier then the child has a 50% chance of having CF. If one parent has CF and the other has two normal genes then there is no chance of the child having CF. If one parent is a carrier and the other has two normal genes then there is no chance of the child having CF. If both parents have CF then there is a 100% chance that the child will also have CF.
What are is the percentages of a child not having cystic fibrosis with parents who both have the trait?
If both parents are just carriers of the gene that causes CF then there is a 75% chance that the child will not have CF. To break it down farther... 25% chance that they will have CF. 50% that they will be a carrier. 25% that they will have two normal genes.
Do carriers have to have cystic fibrosis?
Carriers of cystic fibrosis do not have the disease themselves, as they possess one normal copy and one mutated copy of the CFTR gene. However, they can pass the mutated gene to their children. For a child to develop cystic fibrosis, they must inherit two copies of the mutated gene, one from each parent. Therefore, while carriers do not have cystic fibrosis, they play a crucial role in its inheritance.
If someone was heterozygous for cystic fibrosis what proteins would they make?
If someone is heterozygous for cystic fibrosis, they have one normal CFTR gene and one mutated CFTR gene. This means they would produce both functional and dysfunctional CFTR proteins. The presence of the normal CFTR protein may be sufficient to mitigate the severity of symptoms associated with cystic fibrosis, as they can still have some normal chloride ion transport. However, the overall function and effectiveness of the CFTR protein may be reduced compared to someone with two normal alleles.
Which is a genetic disorder that gene therapy may correct?
Cystic fibrosis is a genetic disorder that gene therapy may correct by introducing a healthy copy of the CFTR gene into cells to restore normal function in affected individuals.
What is cystic fibrosis gene disorder?
The genes on each chromosome control specific functions of the human body. The gene on chromosome 7 produces a protein called cystic fibrosis transmembrane regulator. Mutation in the DNA level of chromosome 7 leads to the absence of this protein which leads to cystic fibrosis. Cystic fibrosis is a recessive disease. It means that both copies of the gene must be defective. An affected person will have abnormal cystic fibrosis transmembrane regulator gene on each chromosome 7. Therefore both biological parents must have an abnormal gene. One abnormal copy is inherited from each parent. A person with one normal gene and one abnormal gene is called a cystic fibrosis carrier. Cystic fibrosis carriers do not show any symptoms but they may pass the abnormal gene to their children. Therefore the parents can be either cystic fibrosis carriers or affected themselves.
