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equivoque
quaquaversal
querquedule
quinquagesima
quinquangular
quinquarticular
quinqueangled
quinquedentate
quinquedentated
quinquefarious
quinquefid
quinquefoliate
quinquefoliated
quinqueliteral
quinquelobate
quinquelobared
quinquelobed
quinquelocular
quinquenerved
quinquennial
quinquennium
quinquepartite
quinquereme
quinquesyllable
quinquevalve
quinquevalvular
quinquivalent
subquinquefid
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What words can you make from seven letters?
One seven letter word, One two letter word and a five letter word, One three letter word and a four letter word, One three letter word and two two letter words, Two three letter words, Three two letter words, A two letter word and a four letter word, A six letter word, A two letter word and a three letter word, A five letter word, Two two letter words, A four letter word, A three letter word, or A two letter word.
Is headshot one word or two?
Two
Is word search one or two words?
Two.
What Two letter words with J in them?
Two letter word with J in them: ja. jo. Note that there are no two (2) letter word that ends with J.
Is q a word in scrabble?
no, has to be at least two letters to be a word in scrabble
What word has two Qs next to each other in it?
"Queue" is a word that has two Qs next to each other in it.
Is the word QS allowed in a game of scrabble?
No.
What is a QS?
In the construction industry, what is the role of a QS??
If no Ls are Qs and all Qs are Js can you then conclude that some Js are Ls?
If no Ls are Qs then the converse is true that no Qs are Ls. If all Qs are Js, then at least some Js are Qs. Therefore, at least some Js are not Ls. You cannot conclude that some Js are Ls, however. It could be that all Js are not Ls. This cannot be concluded from the information given.
What is quantity demanded?
Quantity demanded (QS) is the amount of a product or service wanted by the market. QS is corresponded to quantity supplied (QS) that regards how much of the what is wanted is actually offered. When QD equals QS the market is said to be at equilibrium.
Why is the sum or product of two rational numbers rational?
Suppose p/q and r/s are rational numbers where p, q, r and s are integers and q, s are non-zero.Then p/q + r/s = ps/qs + qr/qs = (ps + qr)/qs.Since p, q, r, s are integers, then ps and qr are integers, and therefore (ps + qr) is an integer.q and s are non-zero integers and so qs is a non-zero integer.Consequently, (ps + qr)/qs is a ratio of two integers in which the denominator is non-zero. That is, the sum is rational.Also p/q * r/s = pr/qs.Since p, q, r, s are integers, then pr and qs are integers.q and s are non-zero integers so qs is a non-zero integer.Consequently, pr/qs is a ratio of two integers in which the denominator is non-zero. That is, the sum is rational.
What does qs mean in typing?
Quad Strike or Quick Strike. (QS)
Why is the sum of two rational numbers always rational numbers?
Suppose p/q and r/s are rational numbers where p, q, r and s are integers and q, s are non-zero.Then p/q + r/s = ps/qs + qr/qs = (ps + qr)/qs. Since p, q, r, s are integers, then ps and qr are integers, and therefore (ps + qr) is an integer. q and s are non-zero integers and so qs is a non-zero integer. Consequently, (ps + qr)/qs is a ratio of two integers in which the denominator is non-zero. That is, the sum is rational.
What does QS mean?
QS can refer to several things depending on the context. In business, QS often stands for "Quantity Surveyor," a professional who estimates and manages construction costs. In healthcare, QS can refer to "Quality of Service," which measures the level of service provided to patients.
How you can add two rational numbers?
If the two rational numbers are expressed as p/q and r/s, then their sum is (ps + rq)/(qs)
Why is the difference between two rational numbers always a rational number?
Suppose x and y are two rational numbers. Therefore x = p/q and y = r/s where p, q, r and s are integers and q and s are not zero.Then x - y = p/q - r/s = ps/qs - qr/qs = (ps - qr)/qsBy the closure of the set of integers under multiplication, ps, qr and qs are all integers,by the closure of the set of integers under subtraction, (ps - qr) is an integer,and by the multiplicative properties of 0, qs is non zero.Therefore (ps - qr)/qs satisfies the requirements of a rational number.
Why is the difference of two rational numbers are rational numbers?
Suppose A and B are two rational numbers. So A = p/q where p and q are integers and q > 0 and B = r/s where r and s are integers and s > 0. Then A - B = p/q - r/s = ps/qs - qr/qs = (ps - qr)/qs Now, p,q,r,s are integers so ps and qr are integers and so x = ps-qr is an integer and y = qs is an integer which is > 0 Thus A-B can be written as a ratio of two integers, x/y where y>0. Therefore, A-B is rational.
