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The cheats for ruby are the cheats for battlefire
I don't think so, I haven't been able to find any.
Fe-59 decays via electron capture to Co-59, which is a stable nuclide. This decay process involves the capture of an inner orbital electron by the nucleus.
Most types of radioactive decay cannot be affected by anything. However, radioactive decay involving electron capture will be affected by the removal of electrons from around the nucleus. In the absence of orbital electrons, it cannot occur at all.
This isn't a straight forward math question. A satellite in orbit at a height of 173 miles and is experiencing orbital decay of 1640 feet a day will eventually come into contact with the upper atmosphere. Atmospheric drag will begin to affect the orbital decay rate, and it will increase. It will not be long before atmospheric drag, which will be heating the satellite, offers so much resistance that the satellite will be burning up and will be slowing down extremely rapidly. It's orbital decay will not be a linear thing as suggested by the problem posed. Only for a while at the start will its decay rate remain constant.
The orbital names s, p, d, and fstand for names given to groups of lines in the spectra of the alkali metals. These line groups are called sharp, principal, diffuse, and fundamental.
The s orbital is the orbital nearest to the nucleus in an atom.
No, a hydrogen orbital does not have a sharp edge. Instead, the electron cloud of a hydrogen orbital becomes less dense as you move away from the nucleus, leading to a gradual decrease in electron probability density rather than a distinct boundary.
4f orbital
The orbital is in the eye socket.
The 2s orbital is larger than the 1s orbital and is higher in energy.
The correct orbital diagram for sulfur can be represented as: 1s2 2s2 2p6 3s2 3p4. This indicates that sulfur has two electrons in the 1s orbital, two in the 2s orbital, six in the 2p orbital, two in the 3s orbital, and four in the 3p orbital.
The orbital configuration for boron is 1s2 2s2 2p1. This means that boron has two electrons in the 1s orbital, two in the 2s orbital, and one in the 2p orbital.