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A radioactive nuclide with a half-life of 8.0252 days will decay to 0.75 of its original size in 3.33 days.

AT = A0 2(-T/H)

0.75 = (1) 2(-T/8.0252)

log2(0.75) = log2(2(-T/8.0252))

-0.415 = -T/8.0252

T = 3.33

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Q: The half life of iodine-131 is 8.0252 days How long will it take for a sample to decay to three-fourths of its original size?
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