Im the Pokemon league champion and according to me, Yes, it is fake. fake Pokemon, fake islands and places, and it has a lot of swearing in. i garantee you it is fake. and i garantee you i talk to much.
First of all, acording to me you talk way more than the first perosn. second of all everybody who beat the game in any pokmeon game is a legue champion.
A fake version of Pokemon gold
Pokemon quartz is fake, but it works and you can play it on your ds or gameboy or you can download the emulator.
there is no real hack to tell you the truth
Pokemon perla is a fake game.
Yes pokemon perla is fake. the fake is on Gameboy Advanced , However if you bought the spanish version of pokemon diamond and perl it would be called pokemon perla & pokemon diamante. The Fake Box Usualy Has A Lucario On The Front Of It
Pokemon Quartz Is A Fake Version Pre-Realeased to Pokemon emerald
Pokemon quartz is fake, but it works and you can play it on your ds or gameboy or you can download the emulator.
Yes, it is a hacked version of sapphire , ruby, and emerald owning this game is illegal and you will go to jail if you own it.
quartz version is illegal and i have no idea how to hack a new Pokemon game
Actually Pokemon Quartz is fake but you can play it on your gameboy or ds. I have it and it is very fun with all new pokemon. If anybody thinks it doesn't work then they obviously don't know.
A fake version of Pokemon gold
treeko is not in the Pokemon quartz version his in ruby,sapphire version's that's all i know where can you find treeko. Im kordell the Pokemon ranger tatah!
there are no deoxys in Pokemon quartz version there r different pokemons, you will find it on other versions. by:kordell the Pokemon ranger
No, its a fake Pokemon
It is not possible to get fake Pokemon on Pokemon Emerald. The only way to get fake Pokemon in any Pokemon game is to play a hacked version.
yes you can it does not matter if its fake cuss i love the game.
Pokemon quartz is fake, but it works and you can play it on your ds or gameboy or you can download the emulator.