It would take 100 graduated cylinders, each with a volume of 10ml, to fill a 1l soda bottle.
5 obviously. 1L=1000ml 200x5=1000ml
1. Fill 5L vessel and pour all 5L into 7L vessel. 2. Fill 5L vessel again and fill the remainder of the 7L vessel (2L...leaving you with 3L in 5L vessel) 3. Empty 7L vessel and pour the 3L from 5L vessel into 7L vessel. 4. Fill 5L vessel again and fill the remainder of the 7L vessel (this will be 4L, as you have already got 3L in 7L vessel from Step 3. Leaving you with 1L in 5L vessel) 5. Empty the 7L vessel. Pour the 1L (from Step 4) from the 5L vessel into the 7L vessel. 6. Fill the 5L vessel and add it to the 1L (from step 5) in the 7L vessel. You now have 6L in the 7L vessel...WATER THE PLANT!1 Kg or 1000 grams
Well, you could fill 1 4L beaker, or 4 1L beakers, or 8 500mL beakers, or 16 250mL beakers ...
1000 ml = 1l 1*5=5 It will take 5 times to fill the container.
There are 1000 milliliters in 1 liter.
1L = 1000mL 600mL x 1L/1000mL = 0.6L
The density of sodium chloride (table salt) is approximately 2.16 g/cm^3. Since 1L of water is equivalent to 1,000 cm^3, the mass of sodium chloride needed to equal 1L would be 2.16 g/cm^3 * 1,000 cm^3 = 2,160 grams.
1L = 1000mL 0.6mL x 1L/1000 = 0.0006L
-fill 5L pour into 7L -fill 5L pour into 7L so that the 7L is now full 5L jar has 3L and 7L has 7L -empty 7L -pour the 3L from the 5 into the 7 -fill 5L pour into 7L so that the 7L is now full 5L jar has 1L and 7L is full -fill 5L (again!) pour into 7L 7L jar now has 6L -fill the 5L jar and pour into the 7L jar so that it is full -since 1L is poured from 5L there is 4L remaining in it. these water pouring questions work by the remainder when multiples of the smaller container are divided by the larger container (that's why the procedure is so repetitive!)
1cm = 1 mL = 1000 cm= 1L =10000 mm = 1L
0.001