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At least two numbers are required to determine an average.

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7y ago
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6y ago

The average of the given three numbers is 16 and 1/3

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6y ago

(16+20+13) ÷ 3 = 16.33 recurring.

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12y ago

13.5

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Q: What is the upper bound of 13?
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17.7 to 1dp lower and upper bound?

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