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A band plays music at 60 dB and then changes to a rock song at 80 dB How many times louder is the rock song?
The difference in decibels between the two sound levels can be calculated using the formula: 10 * log10(Intensity2/Intensity1), where Intensity2 is the intensity of the rock song (80 dB) and Intensity1 is the intensity of the band music (60 dB). Plugging in the values, we get: 10 * log10(10^(8/10)/10^(6/10)) = 10 * log10(100/10) = 10 * log10(10) = 10 * 1 = 10. Therefore, the rock song is 10 times louder than the band music.
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