R = E/I = (12)/(0.1) = 120 ohms
(Make it a big one. It dissipates I2R = 0.01 x 120 = 1.2 watts.)
It depends on the voltage applied across it. But the maximum current is limited by the power-rating of the resistor (power divided by the square of the voltage).
When a dc supply is connected to a resistor, current flows. The current in amps is equal to the supply voltage divided by the resistance in ohms. The power used is the voltage times the current, and that appears as heat in the resistor, which might become hot to touch.
Kirchhoff's Voltage and Current Laws apply to circuits: series, parallel, series-parallel, and complex.If your circuit comprises just a single resistor, then they still apply. For example, the voltage drop across a single resistor will be equal and opposite the applied voltage (Kirchhoff's Voltage Law), and the current entering the resistor will be equal to the current leaving it (Kirchhoff's Current Law).
A resistor doesn't have a power factor. However, if a circuit is pure resistance in nature the power factor will be one when a voltage is applied and a current flows in the circuit. The power factor is a measure of the relative phases of the current and voltage in a circuit.
The voltage across the resistor is whatever voltage is applied. The only maximum here would be a voltage that would damage the resistor. If you think this might happen, you'll have to look up such a voltage from the data sheets.
No. If a voltage is applied across a resistor, a current flows through it.
It depends on the voltage applied across it. But the maximum current is limited by the power-rating of the resistor (power divided by the square of the voltage).
A resistor's resistance is measured in ohms. The higher the resistance the less current will flow with a constant voltage applied across the resistor. In terms of Ohm's Law Voltage = Current x Resistance.
When a dc supply is connected to a resistor, current flows. The current in amps is equal to the supply voltage divided by the resistance in ohms. The power used is the voltage times the current, and that appears as heat in the resistor, which might become hot to touch.
Kirchhoff's Voltage and Current Laws apply to circuits: series, parallel, series-parallel, and complex.If your circuit comprises just a single resistor, then they still apply. For example, the voltage drop across a single resistor will be equal and opposite the applied voltage (Kirchhoff's Voltage Law), and the current entering the resistor will be equal to the current leaving it (Kirchhoff's Current Law).
Current changes across a resistor in direct proportion to the voltage applied. This relationship is described by Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R), or I V/R.
The reason an AC voltage applied across a load resistance produces alternating current is because when you have AC voltage you have to have AC current. If DC voltage is applied, DC current is produced.
Ohm's law: Volts = amps times ohms In the case of a 4 ohm resistor with 1.5 amps of current, the voltage is 6 volts.
Copper can not of itself produce a current. <><><><><> However, resistance, be it copper or some other material, will produce a current if a voltage is applied to it. The rule is Ohm's law: Current = Voltage divided by resistance.
Voltage / Resistance = Current, you do the math
A resistor reduces the flow of current in an electrical circuit, which in turn affects the voltage across the resistor.
A resistor doesn't have a power factor. However, if a circuit is pure resistance in nature the power factor will be one when a voltage is applied and a current flows in the circuit. The power factor is a measure of the relative phases of the current and voltage in a circuit.