top pointer of a stack is the pointer that refers to the top most element of the stack.
There are 4 main widely used stack operations.Operations:* POP - increase stack pointer and return top element * PUSH - putting element into stack's top * TOP - returns data of top element on stack * LENGTH/SIZE - returns number of elements inside stack For more detailed implementation details, please check web links.
You don't. A stack is a last in first out (LIFO) structure so you only have access to the top element in the stack. If you want to locate the smallest element in the stack, you need to pop everything off the stack in order to find it, at which point the stack is completely ruined. The only way to restore a stack is to push every element onto another stack as they are popped off. The other stack will then be the reverse of the original, so you just repeat the process to transfer the elements back to the original stack. You should really be asking why you are using a stack in the first place if the intent is to remove an element other than the top element. A forward list would be a much better option.
No, the whole idea of a stack is that elements can only be added at the top.
Push inserts a value onto the top of the stack. Pop extracts the top value from the stack. These are the two primary operations that can be performed upon a stack. Prior to popping a value, you will first check the stack is not empty, store the top value, then pop the stack. For a stack of type T, you might use the following: if (!stack.empty()) { T value {stack.top()}; // copy top value stack.pop(); // remove value from stack // use value... }
top pointer of a stack is the pointer that refers to the top most element of the stack.
Common operations that can be performed on a stack data structure include push (adding an element to the top of the stack), pop (removing the top element from the stack), peek (viewing the top element without removing it), and isEmpty (checking if the stack is empty).
There are 4 main widely used stack operations.Operations:* POP - increase stack pointer and return top element * PUSH - putting element into stack's top * TOP - returns data of top element on stack * LENGTH/SIZE - returns number of elements inside stack For more detailed implementation details, please check web links.
You don't. A stack is a last in first out (LIFO) structure so you only have access to the top element in the stack. If you want to locate the smallest element in the stack, you need to pop everything off the stack in order to find it, at which point the stack is completely ruined. The only way to restore a stack is to push every element onto another stack as they are popped off. The other stack will then be the reverse of the original, so you just repeat the process to transfer the elements back to the original stack. You should really be asking why you are using a stack in the first place if the intent is to remove an element other than the top element. A forward list would be a much better option.
To efficiently use a stack to sort elements in a data structure, you can follow these steps: Push all elements into the stack. Create a temporary stack to store the sorted elements. While the original stack is not empty, pop an element from the original stack. Compare the popped element with the top element of the temporary stack. If the popped element is greater, push it onto the temporary stack. If the popped element is smaller, keep popping elements from the temporary stack and pushing them back onto the original stack until the temporary stack is empty or the top element is greater. Repeat steps 3-6 until the original stack is empty. The elements in the temporary stack will now be sorted in ascending order. By following these steps, you can efficiently use a stack to sort elements in a data structure.
No, the whole idea of a stack is that elements can only be added at the top.
Push inserts a value onto the top of the stack. Pop extracts the top value from the stack. These are the two primary operations that can be performed upon a stack. Prior to popping a value, you will first check the stack is not empty, store the top value, then pop the stack. For a stack of type T, you might use the following: if (!stack.empty()) { T value {stack.top()}; // copy top value stack.pop(); // remove value from stack // use value... }
Delete is mostly commonly known as pop in stack. The last element inserted into the stack is removed from the stack. Here is an illustration:Consider the stack with the elements 1,2,3,4 inserted in order.1->2->3->4\topThe top of the stack will be pointing to 4. When pop operation is performed, 4 is removed from the stack and the top is made to point to 3. The stack then becomes:1->2->3\top
Just initialize the stack pointer...stack = top;However, this will leak memory if the stored elements contain pointers, so it may be more prudent to pop each element off and delete it instead...while ((element = pop(stack)) != NULL) free (element);
1. If TOP = MAXSTK THEN [Stack already filled?] Print "OVERFLOW" Go to step 4 Endif 2. TOP = TOP + 1 [Increase TOP by 1] 3. Set ST[STOP] = ITEM [Insert ITEM in new TOP position] 4. End
You would need an array to store the actual stack. Better use an ArrayList or some other structure that you can redimension. You'll also need a variable to point to the "top of stack" - the last element added, which is the first element to be taken away.
You would do this if you implement a stack using an array. Using a zero-based index to keep track of the top of the stack (the end of the array) means we must use the value -1 to indicate an empty stack. This is because an array of n elements will have indices 0 through n-1, where index n-1 represents the element at top of the stack. An empty stack has 0 elements, therefore the top of the stack is represented by index -1.